Using only the values given in the table for the function , f(x) = x3-3x-2 , what is the interval of x-values over which the function is decreased. Advertisement ... 3 = 3(x² - 1) We know, any Function f(x) decrease s in interval [a, b] when f'(x) < 0 ... -1 < x < 1. Hence, function f(x) = x³ - 3x - 2 , is decreased in (-1, 1).
135 cubes because if you multiply all the sides you get 2 7/64 so then you multiply that with 1/4 and you get 135/256. Just use the top number. I hope this helps!
