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yarga [219]
3 years ago
13

Colin got 16 out of 80 correct in his test. What fraction of the marks did he get correct? Give your answer in its simplest form

.
Mathematics
2 answers:
expeople1 [14]3 years ago
6 0

Answer:

16/80=8/40

8/40=4/20

4/20=2/10

2/10=1/5

1/5

garri49 [273]3 years ago
6 0

Answer:

1/5

Step-by-step explanation:

16/80= 1/5

1/5 part answered correct

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Find the area of a square with a side measure of 3x − 6 feet. Question 5 options: 9x2−36x+36 sq. ft. 9x2−6 sq. ft. 9x2+36x+36 sq
Sergeeva-Olga [200]

Answer:

9x^2 - 36x + 36 sq. ft.   (the first option).

Step-by-step explanation:

Area of a square of side  d = d^2.

So area of this square = (3x - 6)^2

=  (3x - 6)(3x - 6)

= 3x(3x - 6) - 6(3x - 6)

= 9x^2 - 18x - 18x + 36

= 9x^2 - 36x + 36 sq ft.

4 0
3 years ago
Solve for y 4.2x - 1.4y = 2.1
NeX [460]
4.2x - 1.4y = 2.1
-1.4y = -4.2x + 2.1
y = (-4.2/-1.4)x + 2.1/-1.4
y = 3x - 1.5 <==
3 0
3 years ago
Read 2 more answers
Three consecutive even numbers have a sum where one half of the sum is between 84 and 96
mamaluj [8]

86 *2 = 172

172/3 = 57.33

54 + 56 +58 =168

168/2 =84


56 + 58 +60 = 174

174/2 =87

58 +60 +62 = 180

180/2 = 90

60 +62 +64 = 186

186/2 = 93


62 +64+66 = 192

192/2 = 96


 there are 3 sets of numbers that fall between 84 & 96

 1 set equals 84 and 1 set equals 96

 so if you are counting those there are 5 sets

 

6 0
3 years ago
What is the Inequality and Solution of: The sum of a number and 19 is at least 8.2 ?
Misha Larkins [42]
X + 19 >= 8.2

x >= 8.2 -19 >= -10.8
3 0
4 years ago
Sean and Greg share a 24-ounce bucket of clay. By the end of the week, Sean has used 3 8 of the bucket, and Greg has used 1 4 of
kozerog [31]

Answer:

9

Step-by-step explanation:

Sean and Greg share a 24-ounce bucket of clay

Sean uses 3/8 of the bucket

= 3/8 ×24

= 9 ounce

Greg uses 1/4 if the bucket

= 1/4 ×24

= 6 ounce

= 9+6

= 15 ounce

Therefore the quantity left in the bucket can be calculated as follows

= 24-15

= 9

Hence 9 ounces are left in the bucket

4 0
3 years ago
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