The answer to this question is 290
The number has 2 hundreds so 200
The tens place is 9 more than the ones place so its 9
The last number is 0
I’m pretty sure the equation is 7.50x+20=9.50x+12 then you subtract the x over and now it’ll be -2x+20=12 and then you do 12 - 20 and that is -8 and then -8 divided by -2 and that is 4. so maybe x equals 4? then plug it in and now you have to check your answer so you plug in the 4 and it is 7.50(4)+20=9.50(4)+12 and then that is 50=50. I MAY BE TOTALLY WRONG. but i tried to help at least
Perimeter of the quadrilateral = 48 cm
Solution:
The dimensions of the quadrilateral are 2x, 2x – 1, x – 3 and 3x.
The dimensions of the triangle are x + 3, 5 and x + 3.
<em>Perimeter of the polygon = Sum of the sides of the polygon</em>
The perimeter of the quadrilateral = 2 × Perimeter of the triangle
2x + 2x – 1 + x – 3 + 3x = 2 × (x + 3 + 5 + x + 3)
8x – 4 = 2 × (2x + 11)
8x – 4 = 4x + 22
Add 4 on both sides of the equation.
8x = 4x + 26
Subtract 4x on both sides of the equation.
4x = 26
Divide by 4 on both sides of the equation.
x = 6.5
Perimeter of the quadrilateral = 2 × (x + 3 + 5 + x + 3)
Perimeter of the quadrilateral = 2 × (6.5 + 3 + 5 + 6.5 + 3)
= 2 × (9.5 + 5 + 9.5)
= 2 × 24
= 48
Perimeter of the quadrilateral = 48 cm
1)
8(2^3 x^9y^15)
= ----------------------
4^4 x^16 y^24
x^9 y^15
= -------------------
4 x^16 y^24
1
= -------------------
4 x^7 y^9
2)
2^(6x - 12) = (2^-5)^(3x+12)
2^(6x - 12) = 2^(-15x-60)
6x - 12 = -15x - 60
21x = -48
x = -48/21
x = -16/7
