Answer:
Step-by-step explanation:
it is given that Square contains a chord of of the circle equal to the radius thus from diagram
If Chord is equal to radius then triangle PQR is an equilateral Triangle
Thus 
In triangle PQO applying Pythagoras theorem
Thus length of Side of square 
Area of square
Area of Circle
Ratio of square to the circle
~ Simplifying
-4x + -4 = -7(x + 4)
~ Reorder the terms:
-4 + -4x = -7(x + 4)
~ Reorder the terms:
-4 + -4x = -7(4 + x)
-4 + -4x = (4 * -7 + x * -7)
-4 + -4x = (-28 + -7x)
~ Solving
-4 + -4x = -28 + -7x
~ Solving for variable 'x'.
~ Move all terms containing x to the left, all other terms to the right.
~ Add '7x' to each side of the equation.
-4 + -4x + 7x = -28 + -7x + 7x
~ Combine like terms: -4x + 7x = 3x
-4 + 3x = -28 + -7x + 7x
~ Combine like terms: -7x + 7x = 0
-4 + 3x = -28 + 0
-4 + 3x = -28
~ Add '4' to each side of the equation.
-4 + 4 + 3x = -28 + 4
~ Combine like terms: -4 + 4 = 0
0 + 3x = -28 + 4
3x = -28 + 4
~ Combine like terms: -28 + 4 = -24
3x = -24
~ Divide each side by '3'.
x = -8
~ Simplifying
x = -8
Answer: 41/30
Step-by-step explanation:
1/4 + 1/5 + 11/12 = 41/30 ( 1.36 in alternative form )
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Answer:
true.
Explanation:
still negative.
If a negative number is raised to an even power, the result will be positive. If a negative number is raised to an odd power, the result will be negative
Answer:
Length = 5
Width = 21
Step-by-step explanation:
(x)(x + 16) = 105
x^2 + 16x = 105
x^2 + 16x - 105 = 0
(x - 5) x ( x + 21) = 0
x - 10 = 0
x = 5
x + 21 = 0
x = -21
Now that we have the zeroes.
We have to find the most viable one to put in.
Using -21 would not make sense, so we will use 5.
Plug it in:
x = 5
(5) (5 + 16) = 105
5 ( 21) = 105
