Alright, so every 7 days(a week) in the course of those 42 days, Dave eats 4 sandwiches and 3 pizzas. 42 / 7 = 6 weeks. So every week for 6 weeks Dave ate 4 sandwiches and 3 pizzas. This is a total of:
6 * 4 = 24 sandwiches
6 * 3 = 18 pizzas
This is what he ate in the first 42 days.
Over the next 'x' days, he eats pizza 3 times for every 2 times he eats a sandwich for lunch over the course of 5 days. He's eating 1 more pizza than sandwiches during this time period. Right now he's already eaten 24 sandwiches and 18 pizzas, this is 6 more sandwiches than pizzas. So in order to eat the same amount of pizza and sandwiches, he needs to eat 6 more pizzas. In 5 days he gains 1 pizza over sandwiches. So in 6 * 5 = 30 days he should gain 6 * 1 = 6 pizzas over sandwiches and tie the number of times he had pizza or sandwiches for lunch.
Check your work:
6 * 2 = 12 more sandwiches eaten in these 30 days
6 * 3 = 18 more pizzas eaten in these 30 days
24 + 12 = 36 sandwiches eaten in total
18 + 18 = 36 pizzas eaten in total
Therefore, x = 30 days.
First you must know that what’s outside of the square root is called the coefficient, and it’s the little number outside of the box area.
Next, the number inside the square root or box is called the radicand.
To add radicals you must add coefficients to coefficients, and radicands to radicands.
In your problem the three, which is the radicand, is added to the other 3, which is also the other radicand.
The two outside, which is the coefficient is left outside. The reason the answer has a three outside is that any radical without a number outside is assumed to have the coefficient of one automatically.
One important rule to always remember when adding radicals is that the radicand must be the same number to the other radicand to be added.
I know it can be a bit confusing, but I hope this helped a little.
The answer is 6.
(-3)^2 -3 = 9-3=6
Answer:
2 works
-3 is extraneous
Step-by-step explanation:
sqrt(x + 7) - 1 = x Add 1 to both sides
sqrt(x + 7) = x + 1 Square both sides
(x + 7) = (x + 1 )^2
x + 7 = x^2 + 2x + 1 Subtract x from both sides
0 = x^2 + x + 1 -7
0 = x^2 + x - 6 This will factor
(x + 3)(x - 2) = 0 Find the values for x
x + 3 = 0
x = - 3
x - 2 = 0
x = 2
Now you must check this to see if both values work
sqrt(-3 + 7) - 1 = -3
sqrt(4) - 1 = -3
2 - 1 =? - 3
1 does not equal - 3. Therefore - 3 is extraneous. Try x = 2
sqrt(2 + 7) - 1 = 2
sqrt(9) - 1 = 2
3 - 1 = 2
2 = 2
Answer:
b=3
Step-by-step explanation:
