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d1i1m1o1n [39]
4 years ago
5

HELP ME PLEASE = SIMPLIFYING √578 / √507

Mathematics
1 answer:
jolli1 [7]4 years ago
8 0
<span>First, we will find all factors under the square root: 578 has the square factor of 289.Let's check this width √289*2=√578. As you can see the radicals are not in their simplest form.<span>Now extract and take out the square root √289 * √2. Root of √289=17 which results into 17√2</span></span>Simplified Square Root for √578 is 17√2                                                          <span>
</span><span>First, we will find all factors under the square root: 507 has the square factor of 169.Let's check this width √169*3=√507. As you can see the radicals are not in their simplest form.<span>Now extract and take out the square root √169 * √3. Root of √169=13 which results into 13√3
</span></span>
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