Question

HELP ME PLEASE = SIMPLIFYING √578 / √507

Answer 1

First, we will find all factors under the square root: 578 has the square factor of 289.Let's check this width √289*2=√578. As you can see the radicals are not in their simplest form.Now extract and take out the square root √289 * √2. Root of √289=17 which results into 17√2Simplified Square Root for √578 is 17√2                                                          
First, we will find all factors under the square root: 507 has the square factor of 169.Let's check this width √169*3=√507. As you can see the radicals are not in their simplest form.Now extract and take out the square root √169 * √3. Root of √169=13 which results into 13√3