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3 years ago

I WILL GIVE BRAINLIEST Solve the equation: −4(9 − 3x) = 0

Mathematics

1 answer:

KATRIN_1 [288]3 years ago

7 0

Answer:

Step-by-step explanation:

-4(9-3x)=0

-36+12x=0

12x=0+36

12x=36

x=36/12

x=3

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Which digit in 1,377,207 has a value that is 1/10 the value of the 7 in the ten thousand place?

Nesterboy [21]

Considering the values of the digits in the number, we have that digit 2 has a value that is 1/10 the value of the 7 in the ten thousand place.

<h3>What are the values of the digits in the number 1,377,207?</h3>

We start counting the values from the final number, from 1 and multiplying by 10, hence:

Digit 7 has a value of 1.

Digit 0 has a value of 10.

Digit 2 has a value of 100.

Digit 7 has a value of 1,000.

Digit 7 has a value of 10,000. -> Ten thousand place.

Digit 3 has a value of 100,000.

Digit 2 has a value of 1,000,000.

One tenth of the ten thousand place is a value of 100, hence digit 2 has a value that is 1/10 the value of the 7 in the ten thousand place.

More can be learned about the values of the digits in a number at brainly.com/question/2041524

#SPJ1

5 0

1 year ago

Kevin Horn is the national sales manager for National Textbooks Inc. He has a sales staff of 40 who visit college professors all

Oduvanchick [21]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

Given values:

$38, 40, 41, 45, 48, 48, 50, 50, 51, 51, 52, 52, 53, \\\\$ $54, 55, 55, 55, 56, 56, 57, 59, 59, 59, 62, 62, 62, \\ 63, 64, 65,66, 66, 67, 67, 69, 69, 71, 77, 78, 79, 79$

Total staff=40

In point a:

To calculate the median number first we arrange the value into ascending order and then collect the even numbers of calls that were also made. Its average of the middle terms is thus the median.

The midterms =55 and 59 so,

Median = $\frac{55+59}{2} = \frac{114}{2}=57$

In point b:

First-quarter $Q_1 = \frac{1}{4} \text{number of 8th call}$

$=\frac{1}{4} \times 30 th \\\\= 7.5 th$

The first quarterlies are $7.5th \ \ that \ is = (7+0.5)th\ \ term$

therefore the multiply of 0.5 by calculating the difference of the 7th and 8th term are:

$=0.5 \times 0= 0 \\\\\to Q_1 = 50+0=50 \\\\\to Q_3=\frac{3}{4} \text{number of 8th call} \\\\=\frac{3}{4} \times 30 th \\\\=22.5 \ th = (22+0.5)th \ \ term$

therefore the it is multiply by the 0.5 for the difference of the 22nd and 23rd term:

$= 0.5 \times 1=0.5 \\\\\to Q_3= 63+0.5=63.5$

In point c:

First decile $D_1 = \frac{1}{18} \text{number of 8th call}$

$= \frac{1}{10} \times 30 th \\\\= 3rd \ \ term\\\\\to D_1= 41 \\\\\to D_9= \frac{9}{10} \times 8\ th\ call\\\\=\frac{9}{10} \times 30 th \\\\=27th \ \ term\\\\\to D9 = 67$