The first one is -4 and the second one is 6.
This isn't really a geometry problem. It's just an addition of fractions.
You know that 'perimeter' means 'the distance all the way around'.
And you know the length of all the sides of the parallelogram.
All you need to do is add them up !
(13/12) + (3/13) + (13/12) + (3/13) = the perimeter
Notice that two of the sides are equal, and the other two sides are also equal.
So you can make the job a little easier if you add up the twelfths first
(13/12) + (13/12) = 26/12
and then add up the thirteenths ...
(3/13) + (3/13) = 6/13 .
Now, the perimeter looks a little bit less complicated.
It's just
(26/12) + (6/13) = the perimeter.
This is the tough part. Before you can add fractions, they need to have
a common denominator.
The smallest common denominator for 12ths and 13ths is <em>156 </em>!
Change each fraction to (<em>something over 156</em>), and add um up.
I'll leave that part to you.
Answer:
You are trying to find the x-value when the y-value is 2. On the graph, the x-value is -3 when the y-value is 2. So, the x-value when f(x)=2 is -3.
:)
The vertex would be the point on the right angle like the tip of the right angle
You have to get a common denominator so
3 x 3 = 9
5 x 3 = 15
So now we have 9/15 + 4/15 which is 13/15.
The answer is 13/15
