Answer:
Cost of each ticket bought by Peter = $8 for each ticket
Step-by-step explanation:
Given:
Number of ticket bought by Peter = 9 tickets
Amount paid by Peter for tickets = $72
Find:
Cost of each ticket bought by Peter
Computation:
Cost of each ticket bought by Peter = Amount paid by Peter for tickets / Number of ticket bought by Peter
Cost of each ticket bought by Peter = 72 / 9
Cost of each ticket bought by Peter = $8 for each ticket
7/12 ............................................
Answer:
The data we have is:
The acceleration is 3.2 m/s^2 for 14 seconds
Initial velocity = 5.1 m/s
initial position = 0m
Then:
A(t) = 3.2m/s^2
To have the velocity, we integrate over time, and the constant of integration will be equal to the initial velocity.
V(t) = (3.2m/s^2)*t + 5.1 m/s
To have the position equation, we integrate again over time, and now the constant of integration will be the initial position (that is zero)
P(t) = (1/2)*(3.2 m/s^2)*t^2 + 5.1m/s*t
Now, the final position refers to the position when the car stops accelerating, this is at t = 14s.
P(14s) = (1/2)*(3.2 m/s^2)*(14s)^2 + 5.1m/s*14s = 385m
So the final position is 385 meters ahead the initial position.
Answer:
Your answer should be 13
Step-by-step explanation:
You were given 25, so you need to work backwards. First, multiply the 25 by 3 to get 75. Then Add 6, and you end with 81. Afterwards, subtract 3 from 81 to get 78, then divide by 6 to get 13.
Answer:
No
Step-by-step explanation:
