Let's find the slope of this line. Going from (-7, -7) to (-6, 3), the "run" is +1 (this is the increase in x) and the "rise" is -10 (y increases by 10). Thus, the slope, m, is m = rise / run = 10 / 1 = 10.

Using the point-slope version of the equation of a straight line, we get

y + 7 = 10(x + 7)

Performing the multiplication results in

y + 7 = 10x + 70.

Rearranging these terms in the form Ax + By = C, we get:

-10x + y = 63

Check this by substituting -6 for x and 3 for y:

-10(-6) + 3 = 63 This is TRUE

5 0

3 years ago

First To Answer Gets Brainliest!

Rufina [12.5K]

Between is 12121 and141414

4 0

3 years ago

Read 2 more answers

The weight of high school football players is normally distributed with a mean of 195 pounds and a standard deviation of 20 poun

Firlakuza [10]

Answer:

The probability of a player weighing more than 238

P( X > 238) = 0.0174

Step-by-step explanation:

Step(i):-

Given mean of the normally distribution = 195 pounds

Given standard deviation of the normally distribution

= 20 pounds.

Let 'x' be the random variable of the normally distribution

Let X = 238

$Z = \frac{x-mean}{S.D} = \frac{238-195}{20} = 2.15$

Step(ii):-

The probability of a player weighing more than 238

P( X > 238) = P( Z> 2.15)

= 1 - P( Z < 2.15)

= 1 - ( 0.5 + A(2.15)

= 1 - 0.5 - A(2.15)

= 0.5 - 0.4821 ( from normal table)

= 0.0174

The probability of a player weighing more than 238

P( X > 238) = 0.0174

4 0

3 years ago

The measures of the angles of a quadrilateral are x+15, 2x, x-45, and 2x-60. What types of quadrilaterals could this be?

BabaBlast [244]

I think the answer would be C) | and ||

7 0

4 years ago