Answer:
Explanation:
1.
Cathepsin is involved in programmed cell death, it is a lysosomal enzyme and the reason it is found in the ER fraction instead of the lysosomal fraction is because of its c terminal KDEL sequence. this sequence ia a retrieval for protein and causes a backward movement of protein back to endoplasmic reticulum. that is why cathepsin seems to have localised in ER instead of the lysosomal fraction
2 It does not bind to mannose-6-phosohate receptor because this glycosylation process does not occur in the E.R but in Golgi bodies. because of the KDEL sequence this glycosylation of cathepsin would not occur and cathepsin would go through affinity column without any form of binding to receptor.If cathepsin can get to the Golgi then glycolysation with Mannose6phospate can occur.
Answer:
sensation
Explanation:
sensation provides the taste to the brain
Even though one may assume the largest population of camels in the wild are found in Arabian countries, that is actually not true - the correct answer is Australia, as a matter of fact.
There are a lot of wild camels in the Australian desert, because the 'lifestyle' there suits them most. Camels came to Australia in the 1840s and liked the hot air they found there.
Answer: Option C. "Plasma cells"
Explanation:
An antibody can be defined as a protein produced by the plasma cells which are utilize by immune system able to bind with specific antigen that protects body from diseases.
Plasma cells are antibody-producing cell that originates from B cell. The antibody produced from plasma cells are released into body and lymph, these antibody molecules bind to the target antigen and allow destruction or neutralization.
Hence, the correct option is C.
Cell A is more efficient at exchanging substances due to larger surface area to volume ratio.
Cell A is more efficient at exchanging substances with the surrounding environment than cell B because it has the larger surface-area-to-volume ratio. Larger surface area of the cell exchanges more substances with the surrounding environment while on the other hand, lower surface area of the cell exchanges less materials with the environment so we can conclude that cell A is more efficient at exchanging substances due to larger surface area to volume ratio.
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