Question

Find an expression for the height of a parallelogram whose area is represented by 2x^3 − x^2 − 20x + 3 and whose base is represented by (x + 3).

Answer 1

Answer:

The height of parallelogram is $2x^2-7x+1$

Step-by-step explanation:

Area of parallelogram =$Base \times Height$

Area of parallelogram = $2x^3 -x^2 -20x + 3$

Base of parallelogram = x+3

So, $2x^3-x^2-20x + 3 = height \times (x+3)$

$\frac{2x^3- x^2 -20x + 3}{x+3}= height\\2x^2-7x+1=Height$

Hence The height of parallelogram is $2x^2-7x+1$