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Goryan [66]
4 years ago
6

Find an equation for the line that passes through the points (2,-5) and (-6,-3)

Mathematics
1 answer:
SVEN [57.7K]4 years ago
8 0
Y=-1/4x-9/2
Not sure if that’s correct but I tried
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What is slope in urebcirbicrbcrc
valina [46]

Answer:

if u put that in latin then in spanish then back in english then someone might actually be able to answer that

Step-by-step explanation:

4 0
3 years ago
Consider the differential equationy′′+3y′−10y=0.(a) Find the general solution to this differential equation.(b) Now solve the in
RSB [31]

Answer:

Y= 2e^(5t)

Step-by-step explanation:

Taking Laplace of the given differential equation:

s^2+3s-10=0

s^2+5s-2s-10=0

s(s+5)-2(s+5) =0

(s-2) (s+5) =0

s=2, s=-5

Hence, the general solution will be:

Y=Ae^(-2t)+ Be^(5t)………………………………(D)

Put t = 0 in equation (D)

Y (0) =A+B

2 =A+B……………………………………… (i)

Now take derivative of (D) with respect to "t", we get:

Y=-2Ae^(-2t)+5Be^(5t)   ....................... (E)

Put t = 0 in equation (E) we get:

Y’ (0) = -2A+5B

10  = -2A+5B ……………………………………(ii)

2(i) + (ii) =>

2A+2B=4 .....................(iii)

-2A+5B=10 .................(iv)

Solving (iii) and (iv)

7B=14

B=2

Now put B=2 in (i)

A=2-2

A=0

By putting the values of A and B in equation (D)

Y= 2e^(5t)

6 0
4 years ago
Solve.<br> - 5 - 3 1 / 2 = 0<br> 21<br> Done
patriot [66]
This equation does not have an answer
5 0
3 years ago
What are the roots of x^2-4x+4?
Bezzdna [24]
The roots are just the zero value of the formula. To find these, we factor:

(x - 2)(x - 2)

(x - 2)^2

to make this into a zero, we set x-2 = 0, then solve for x

x = 2

If x = 2, then the brackets = 0, and those are the roots

The roots are x = 2

Leave a comment if you couldn’t understand, and I’ll try to answer.
3 0
4 years ago
Read 2 more answers
What is the answer for r if the equation is
Vlad [161]

9514 1404 393

Answer:

  r = √(V/(πh))

Step-by-step explanation:

To solve for r, "undo" what has been done to r. The "undo" is generally in the reverse order. Here, we have ...

  • r is squared
  • the square is multiplied by πh

To undo these operations, we ...

  V/(πh) = r² . . . . . . . . divide by πh

  √(V/(πh)) = r . . . . . . take the square root

  r = √(V/(πh))

7 0
3 years ago
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