$\frac{5}{8} +\frac{6}{7} =\frac{5*7}{8*7} +\frac{6*8}{7*8}\\\\=\frac{35}{56}+\frac{48}{56}=\frac{35+48}{56} \\\\=\frac{83}{56}\\ =1\frac{27}{56} \\2\frac{5}{8}+9\frac{6}{7}=11+1\frac{27}{56}\\=12\frac{27}{56}$

4 0

3 years ago

A puppy weighed 2kg.

olchik [2.2K]

Answer:

$3.5 - 2 \times 100 \div 2$

6 0

2 years ago

Read 2 more answers

An object is launched at 28 meters per second (m/s) from a 336-meter tall platform. The equation for the object's height s at ti

kondaur [170]

Answer:343 m

Step-by-step explanation:

Given

launch velocity of object is $u=28\ m/s$

height of Platform $h=336\ m$

height of object is given by

$s(t)=-7t^2+14t+336$

For maximum height velocity of object is zero

i.e. $\frac{ds}{dt}=0$

$\frac{ds}{dt}=-14t+14+0=0$

$t=\frac{14}{14}=1\ s$

Therefore after 1 sec object achieves maximum height

$s(1)=-7(1)+14(1)+336$

$s(1)=343\ m$

3 0

4 years ago

Supply the missing reasons to complete the proof

Sladkaya [172]

3. Congruent by AAS

4. CPCTC

8 0

3 years ago