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Artemon [7]
3 years ago
7

Jim has only dimes and nickels in his coin bank. He has 37 coins with a total value of $2.65.

Mathematics
2 answers:
Bingel [31]3 years ago
7 0
Jim has 21 nickels. I hope this helps you out; have a blessed day!
guajiro [1.7K]3 years ago
4 0

Answer:

21

Step-by-step explanation:

Let x represent the number of dimes and y represent the number of nickels.  The total number of coins is 37; this gives us the equation

x+y = 37

Each dime is worth ten cents, or 0.10, and each nickel is worth five cents, or 0.05.  The total amount of money is given by

0.10x+0.05y = 2.65

This gives us the system

\left \{ {{x+y=37} \atop {0.10x+0.05y=2.65}} \right.

To solve this, we will use substitution.  We will isolate x in the first equation:

x+y=37

Subtract y from each side:

x+y-y = 37-y

x = 37-y

Substitute this into the second equation:

0.10(37-y)+0.05y = 2.65

Using the distributive property,

0.10(37)-0.10(y)+0.05y = 2.65

3.70-0.10y+0.05y = 2.65

Combining like terms,

3.70-0.05y = 2.65

Subtract 3.70 from each side,

3.70-0.05y-3.70 = 2.65-3.70

-0.05y = -1.05

Divide both sides by -0.05:

-0.05y/-0.05 = -1.05/-0.05

y = 21

There were 21 nickels.

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