Please help I don’t know how to do this! It’s circle theorem geometry
1 answer:
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Answer:
Step-by-step explanation:
The equation of the line through the point &
can be represented by:
Making m the subject;
∴
we need to carry out the equation of the line through (0,1) and (1,2)
i.e
y - 1 = m(x - 0)
y - 1 = mx
where;
m = 1
Thus;
y - 1 = (1)x
y - 1 = x ---- (1)
The equation of the line through (1,2) & (4,1) is:
y -2 = m (x - 1)
where;
∴
-3(y-2) = x - 1
-3y + 6 = x - 1
x = -3y + 7
Thus: for equation of two lines
x = y - 1
x = -3y + 7
i.e.
y - 1 = -3y + 7
y + 3y = 1 + 7
4y = 8
y = 2
Now, y ranges from 1 → 2 & x ranges from y - 1 to -3y + 7
∴
Answer: Choice B
(-1,0), (-1,-2), (-3, -1), and (-3, -2)
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Explanation:
Let's focus on the point (2,0)
If we shift it 3 units to the left, then we subtract 3 from the x coordinate to get 2-3 = -1 as its new x coordinate. The y coordinate stays the same.
That means we move from (2,0) to (-1,0)
Based on this alone, choice B must be the answer as it's the only answer choice that mentions (-1,0).
If you shifted the other given points, you should find that they land on other coordinates mentioned in choice B.
