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Ilya [14]
3 years ago
9

What is the remainder when 26 is divided by 6

Mathematics
1 answer:
kenny6666 [7]3 years ago
6 0
4.3 repeating

Hope this helps.
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Part 2 of math help me please
serious [3.7K]

Answer:

<1 = <5 is True

<2 = <4 is True

<2 = <7 is False

<3 and <6 are not a linear pair

<4 and <5 are not supplementary angles

m<5 is 75°

m<11 is 75°

m<16 is 65°

4 0
3 years ago
How can I make an equation that equals 74 with using the digits/numbers 1 2 3 4 and 0 once and only once in the equation. Every
nexus9112 [7]

Answer:

A mathematical equation is an equation with zero or one variables (e.g., 9 = 6 + 3; 9 = x + 3), whereas an algebraic equation

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
(10 points) What type of slope does the line y = -3 have?
lakkis [162]

Answer: It has 0 slope.

Step-by-step explanation:

y= 0(x) -3  this is an equal equation of the line so the slope has to be always zero.

8 0
3 years ago
Write the equation of a line in slope-intercept form that passes through the given points.
ruslelena [56]

Answer:

<h2>         y = 0.25x + 2</h2>

Step-by-step explanation:

\bold{slope\, (m)=\dfrac{change\ in\ Y}{change\ in\ X}=\dfrac{y_2-y_1}{x_2-x_1}}

(0, 2)    ⇒     x₁ = 0,  y₁ = 2

(-4, 1)     ⇒     x₂ = -4,  y₂ = 1

So the slope:

\bold{m=\dfrac{1-2}{-4-0}=\dfrac{-1}{-4}=0.25}

The point-slope form of the equation of the line passing through point (x₀,y₀) and with slope m is:  y - y₀ = m(x - x₀)

m = 0.25

(0, 2)    ⇒     x₀ = 0,  y₀ = 2

Therefore:

               y - 2 = 0.25(x - 0)

               y - 2 = 0.25x                  {add 2 to both sides}

               y = 0.5x + 2          ←  the slope-intercept form of the equation

5 0
3 years ago
Find the equation of a line that passes through (-2,4) and (1,-2)
Basile [38]

\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{-2}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-2}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{1}-\underset{x_1}{(-2)}}}\implies \cfrac{-6}{1+2}\implies \cfrac{-6}{3}\implies -2

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{-2}[x-\stackrel{x_1}{(-2)}]\implies y-4=-2(x+2) \\\\\\ y-4=-2x-4\implies y = -2x

8 0
3 years ago
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