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maxonik [38]
4 years ago
6

10 points! Please Help!

Mathematics
1 answer:
AnnyKZ [126]4 years ago
4 0
I imagine it is C as the distance is 778million km. The closest answer would be 7.2•10^8, and if it were to the power of 9 it would be too large a number to make sense. Hope this helps!
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Please help with this
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If f(x)= 6x+7, determine the value of f(-5)
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I think you're supposed to substitute -5 into x. So now the equation is
f(-5)= 6(-5) +7.
f(-5)= -30+7
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As a result, the value of f(-5) is -23
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If 5(3x-1)=55 what is the value of 2x-2
cricket20 [7]

Hey ! there

Answer:

  • Value of 2x - 2 is <u>6</u><u> </u><u>.</u>

Step-by-step explanation:

In this question we are provided with an equation that is <u>5</u><u> </u><u>(</u><u> </u><u>3x</u><u> </u><u>-</u><u> </u><u>1</u><u> </u><u>)</u><u> </u><u>=</u><u> </u><u>5</u><u>5</u><u> </u>and we are asked to find the value of <u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>2</u><u> </u><u>.</u>

Firstly , we need to find the value of x . So we need to solve the equation .

<u>SOLUTION</u><u> </u><u>:</u><u> </u><u>-</u>

\quad \longmapsto \qquad \: 5(3x - 1) = 55

<u>Step </u><u>1</u><u> </u><u>:</u> Dividing with 5 on both sides :

\quad \longmapsto \qquad \: \dfrac{ \cancel{5}(3x - 1)}{ \cancel{5}}  = \cancel{\dfrac{55}{5} }

On cancelling , We get :

\quad \longmapsto \qquad \:3x - 1 = 11

<u>Step </u><u>2</u><u> </u><u>:</u> Adding 1 on both sides :

\quad \longmapsto \qquad \:3x -  \cancel{1} +  \cancel{1} = 11 + 1

On simplifying , We get :

\quad \longmapsto \qquad \:3x = 12

<u>Step </u><u>3 </u><u>:</u> Dividing with 3 on both sides :

\quad \longmapsto \qquad \: \dfrac{ \cancel{3}x}{ \cancel{3}}  =  \cancel{ \dfrac{12}{3} }

We get ,

\quad \longmapsto \qquad \:    \underline{\boxed{\frak{x = 4}}}

→ Therefore , value of x is <u>4</u><u> </u><u>.</u>

<u>Verifying</u><u> </u><u>:</u><u> </u><u>-</u>

Now we are verifying whether our answer is wrong or right . So ,

  • 5 ( 3x - 1 ) = 55

  • 5 { 3( 4 ) - 1 } = 55

  • 5 ( 12 - 1 ) = 55

  • 5 ( 11 ) = 55

  • L.H.S = R.H.S

  • Hence , Verified .

Therefore , our value of x is <u>correct</u><u>/</u><u>valid </u><u>.</u>

<u>We </u><u>need </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>2</u><u> </u><u>.</u><u> </u>

<u>\quad \longmapsto \qquad \:2x - 2</u>

So substituting value of x in it :

<u>\quad \longmapsto \qquad \:2( \bold{4}) - 2</u>

Multiplying 2 with 4 :<u> </u>

<u>\quad \longmapsto \qquad \:8 - 2</u>

Subtracting 2 from 8 :

\quad \longmapsto \qquad \:    \blue{\underline{\boxed{\frak{6}}}}  \quad \: \bigstar

  • <u>Henceforth</u><u>,</u><u> </u><u>value </u><u>of </u><u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>2</u><u> </u><u>is </u><u>❝</u><u> </u><u>6</u><u> </u><u>❞</u><u>.</u>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
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