Answer:
The total mechanical energy is 0.712 J.
Step-by-step explanation:
A blue 573 g mobile is moving on a metal rail. If on the mobile, the spring exerts a force to the right of modulus 0.85 N and in the indicated position the kinetic energy of the mobile-spring system is 0.47 J and its elastic potential energy is 0.242 J. Determine the mechanical energy of the system mobile-spring in the position shown as indicated in the figure.
The total mechanical energy is given by the sum of the kinetic energy and the potential energy.
Kinetic energy = 0.47 J
Potential energy = 0.242 J
The total mechanical energy is
T = 0.47 + 0.242 = 0.712 J
When
the ball is in the ground, its height is basically equal to zero thus making
our equation,
<span> -16t^2 + 272t + 1344 = 0</span>
Simplifying
the equation will give us,
<span> - t^2 + 17t + 84 = 0 or t^2 – 17t – 84 = 0</span>
Factoring
out the equation will give us,
<span> (t – 21)(t + 4) = 0</span>
Thus,
t = 21 or t = -4. -4 is an extraneous root. Thus, the answer is t = 21.
<span>Answer:
21 seconds</span>
<span>7/8 - 1/4 = 7/8 - 2/8 = 5/8</span>
2+a / 2 = 4 and b+6 /2 = 10
2+a=8. and. b+6 = 20
a=6. and. b=14
(a,b) , the other endpoint, is thus (6,14)
