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3 years ago

Factor the followingX^2+3x+2x^2+15x+50

Mathematics

2 answers:

Xelga [282]3 years ago

8 0

Answer:

1) $(x+1)(x+2)$

2) $(x+5)(x+10)$

Step-by-step explanation:

You can factorize the quadratics equations by applying the proccedure shown below:

1) $x^2+3x+2$

Find two number whose sum is 3 and whose product is 2.

These would be 1 and 2.

Rewrite it as folowing:

$(x+1)(x+2)$

2) $x^2+15x+50$

Find two number whose sum is 15 and whose product is 50.

These would be 5 and 10.

Therefore, you can rewrite it as folowing:

$(x+5)(x+10)$

Mars2501 [29]3 years ago

4 0

The 1st one is (x+2)(x+1)

The 2nd one is (x+5)(x+10)

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ikadub [295]

Answer:

$\boxed{D) ~(-6,-12)}$

Step-by-step explanation:

$\boxed{Rule}:-$

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3 0

3 years ago

Read 2 more answers

In a city with a population of 1 million, 500 people have been diagnosed with cancer, whereas the rest of the people do not have

Leni [432]

Class distribution is considered to be normal using normal approximation to binomial.

A frequency distribution is a table that shows classes or intervals of data with a count of the number in each class.

Given :

In a city with a population of 1 million

i.e Population size (N) = 1 million = 1000000

From which 500 people have been diagnosed with cancer

Let X : No. of people have been diagnosed with cancer

X = 500

Population proportion (p) :

p = XNp =5001000000p = 0.0005

So , the proportion of people who do not have cancer (q)=1-p

=1-0.0005

=0.9995

Here the distribution of X is Binomial

Such that :

i. No. of trials are fixed

ii. Probability of success is constant (p=0.0005)

iii. Possible outcomes are two (having cancer or not)

Here we can use normal approximation to Binomial

Because N is very large

So class distribution is considered to be normal using normal approximation to binomial.

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5 0

2 years ago

What is an equivalent fraction to 3/10

ollegr [7]

Answer:

0.3

Step-by-step explanation:

3/10=0.3

4 0

3 years ago

Read 2 more answers

Cheryl plans to bake cookies tomorrow and needs to purchase chocolate chips and pecans for no more than $25 total. Chocolate chi

boyakko [2]

The inequality that correctly represents this scenario is given as follows:

$2x + 5y \leq 25$

The graph is given at the end of the question.

<h3>What is a system of inequalities?</h3>

A system of inequalities is when two or more variables are related, and inequalities are built to find the values of each variable.

In this problem, the variables are given as follows:

Variable x: number of chocolate chips purchased.

Variable y: number of pecans sold.

Chocolate chips are $2 per pound and pecans are $5 per pound. She wants to spend at most $25, hence:

$2x + 5y \leq 25$

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6 0

2 years ago

Mateo compró un artefacto gastando los 3/7 de su dinero, quedándole 360 soles, ¿Cuál era el dinero que tenía Mateo al inicio?

Debora [2.8K]

Answer:

840 soles

Step-by-step explanation:

Sea la cantidad de dinero que Mateo tenía al principio = x

Mateo compró un artefacto gastando 3/7 de su dinero, dejándole 360 soles,

Por eso,

3/7 × x = 360 soles

3x / 7 = 360 soles

Multiplicar cruzada

3x = 7 × 360 soles

x = 7 × 360 soles / 3

x = 840 soles

Por tanto, el dinero que tenía Mateo al principio es de 840 soles

5 0

3 years ago

Factor the followingX^2+3x+2x^2+15x+50​

Factor the followingX^2+3x+2x^2+15x+50