Answer:
1)=3(3t^2w-1)
2)=(4x-17)(x-5)
Step-by-step explanation:
1) =Factor out 3
2) =in order to factor an integer we need to repeatedly divide it by the ascending sequence of primes (2,3,5)
number of times each prime divides the original integer becomes it's exponent in the final result. for this equation prime number 2 to the power of 2 =4
2^2(x - 5)² + 3 (x - 5)
we need to factor GCF ( greatest common factor)
The resulting term is a product of GCF and original expression divided by GCF. in equation the GCF = x-5
(x-5)(2^2(x-5)^2/x-5 + 3(x-5)/x-5 )
Need to reduce fraction to lowest terms. Done by dividing out factors that appear both in numerator and denominator. Common factor in equation is x-5
(x-5)(2^2(x-5)^2-1+3)
need to evaluate a power by multiplying the base by itself as many times as the exponent indicates. in equation base 2 will be multiplied by itself twice.
(x-5)(4(x-5)+3)
Expand this term by multiplying a term and an expression. Following product A(B+C)=AB+AC
in equation the resulting expression will consist of 2 terms:
first term is a product of 4 and X
Second term is a product of 4 and -5
(x-5)((4x-4*5)+3)
Numerical factors in this term have been multiplied
(x-5)((4x-20)+3)
We need to get rid of expression parentheses. If there is a negative sign in front of it , each term within expression changes sign. Otherwise expression remains unchanged. In equation there are no negative expression s.
(x-5)(4x-20+3)
Simplify = (4x-17)(x-5) or (x-5)(4x-17)
