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storchak [24]
3 years ago
10

You have a gross income of $117,151 and are filing your tax return singly. You claim one exemption and can take a deduction of $

2,713 for interest on your mortgage, an adjustment of $2,791 for business losses, an adjustment of $1,346 for alimony, a deduction of $2,086 for property taxes, a deduction of $2,376 for contributions to charity, and an adjustment of $1,091 for contributions to your retirement fund. The standard deduction for a single filer is $5,700, and exemptions are each worth $3,650. What is the difference between your adjusted gross income and your taxable income?
Mathematics
2 answers:
Olin [163]3 years ago
7 0
<span>$10,825
Is your answer
</span>
Grace [21]3 years ago
3 0
Answer is $10,825 did that test too (C)
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Aaron borrows $150 from his friend Austin. He promises to pay back the money in 4 monthly installments. Each month he wants to p
Maurinko [17]
  1. Answer C. $80
  • 80-40-20-10=150
5 0
3 years ago
find the equation of a cubic function whose graph passes through points (3,0) and (1,4) and is tangent to x-axis at the origin
Tomtit [17]

Answer:

y = -2x^2(x - 3)

Step-by-step explanation:

<em><u>Preliminary Remark</u></em>

If a cubic is tangent to the x axis at 0,0

Then the equation must be related to y = a*x^2(x - h)

<em><u>(3,0)</u></em>

If the cubic goes through the point (3,0), then the equation will become

0 = a*3^2(3 - h)

0 = 9a (3 - h)

0 = 27a - 9ah

from which h = 3

<em><u>From the second point, we get</u></em>

4 = ax^2(x - 3)

4 = a(1)^2(1 - 3)

4 = a(-2)

a = 4 / - 2

a = -2

<em><u>Answer</u></em>

y = -2x^2(x - 3)

 

3 0
3 years ago
HELP ASAP!!!
Nat2105 [25]
A , the seal is a carbavore
8 0
2 years ago
T = an + b ( solve for b )
Butoxors [25]
B=t-am is the correct answer:)
6 0
3 years ago
10x^3 y^-5 z^-2 if x=3 y=2 and z=5 express your answer as a reduced fraction
sineoko [7]

Answer:

\large\boxed{\dfrac{27}{80}}

Step-by-step explanation:

Put x = 3, y = 2 and z = 5 to the given expression 10x^3y^{-5}z^{-2}:

10(3^3)(2^{-5})(5^{-2})\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=\dfrac{10(27)}{(2^5)(5^2)}=\dfrac{270}{(32)(25)}=\dfrac{270}{800}=\dfrac{27}{80}

7 0
3 years ago
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