3x + 4y = 16
-4x - 3y = -19
4( 3x + 4y = 16)
3( -4x - 3y = -19)
Distribute
12x + 16y = 64
-12x - 9y = -57
Now subtract both equations
7y = 7
/7 on both sides
y = 1
Substitute y = 1 in one of the equations.
3x + 4y = 16
3x + 4(1) = 16
-4 on both sides
3x = 12
/3 on both sides
x = 4
Answer:
x = 4
y = 1
Answer:
I believe this is correct
A is FALSE
B is TRUE
C is FALSE
Answer:
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Step-by-step explanation:
equation.
2(m+10)=4(m−15)
(2)(m)+(2)(10)=(4)(m)+(4)(−15)(Distribute)
2m+20=4m+−60
2m+20=4m−60
Step 2: Subtract 4m from both sides.
2m+20−4m=4m−60−4m
−2m+20=−60
Step 3: Subtract 20 from both sides.
−2m+20−20=−60−20
−2m=−80
Step 4: Divide both sides by -2.
−2m−/2=−80/−2
m=40
