Answer:
-2(-12-7 g)
Step-by-step explanation:
hope this helps :)
Given a radius 
, the volume of a sphere is given by
We can solve this formula for the radius, given the volume:
![r=\sqrt[3]{\dfrac{3V}{4\pi}}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cdfrac%7B3V%7D%7B4%5Cpi%7D%7D)
We can plug our value for the volume to get the radius:
![r=\sqrt[3]{\dfrac{3\cdot 12\pi}{4\pi}}=\sqrt[3]{9}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cdfrac%7B3%5Ccdot%2012%5Cpi%7D%7B4%5Cpi%7D%7D%3D%5Csqrt%5B3%5D%7B9%7D)
Answer:
116*
Step-by-step explanation:
36* + 28* = 64*
180* - 64* = 116*
Sin60=DF/FE
Root 3/2= DF/ 18 Root 3
DF= 18*3/2
DF= 27 units
cos60=DE/FE
1/2=DE/18 Root 3
DE= 18 Root 3/2
DE= 9 Root 3 units
Evaluate 2^3+5x(6+4)÷2 following Order of Operations rules (PEMDAS):
Work within parentheses is done first, followed by exponentiation, and then mult. and div., and finally add'n. and subtr'n.
Thus, 2^3+5x(6+4)÷2 becomes 2^3+5x(10)÷2
8 + 50x/2
8 + 25x
