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STatiana [176]
3 years ago
5

my number has 8 tens. the digital in the ones place is greater than the digit in the tens place. what my number is

Mathematics
2 answers:
Dima020 [189]3 years ago
8 0
Your number has to be 80 and if the  number in the ones place is greater than the 8 in the tens place the answer has to be 9  so 89 is the answer
Vlada [557]3 years ago
5 0
Your answer to this is 89
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Find the value of the expression 63 - 21 + (3 x 11)
bixtya [17]

Answer: First solve the parentheses using order of operations. Then add and subtract from left to right.

Demo:

(3 * 11) = 33

Equation now looks like:

63 - 21 + 33

63 - 21 = 42

Equation now looks like:

42 + 33

42 + 33 = 75

The value of this expression is 75.

5 0
3 years ago
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MN is a diameter of a circle with centre ' O ' . If BD = CD , prove that ∠OAD = ∠OCD
Varvara68 [4.7K]

Answer:

\sf \: Proved \: \angle \: OAD  \:  =  \angle \: OCD

Step-by-step explanation:

<em>Given:</em>

Mn is diameter of circle having centre O

and BD = OD,

<em><u>To prove that:</u></em>

<u>\angle \: OAD  \:  =  \angle \: OCD</u>

<em>Solution:</em>

Join the points O and B and draw OB,

On joining the line,

in ∆OCD and ∆OBD,

OC =OB → (Radius of same circle)

BD =CD → (from given)

OD =OD → (Common side in both the triangles)

Hence ∆OCD and ∆OBD are congruent from SSS property.

so we can say that,

\angle \: OBD  \:  =  \angle \: OCD

Consider above prove as statement A

Corresponding angles of congruent traingle.

in ∆ OAB,

OA = OB (radius of same circle)

hence ∆OAB is an isosceles traingle.

We know that opposite angle of isosceles traingle are always equal. hence,

\angle \: OBD  \:  =  \angle \: OAB \\ \angle \: OAB  \:  =  \angle \: OAD (same \: angles) \\ \angle \: OBD  \:  =  \angle \: OAD

Consider above prove as statement B

From Statement A & B we can say that

\angle \: OAD  \:  =  \angle \: OCD

<em>Thanks for joining brainly community!</em>

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Answer:

Step-by-step explanation:

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Answer:

Answer: No

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