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2 years ago

6

Ivan drove 737 miles in 11 hours. At the same rate, how long would it take him to drive 603 miles?

2 answers:

choli [55]2 years ago

5 0

It will take him 9 hours to drive 603 miles.

katrin2010 [14]2 years ago

4 0

737 miles per 11 hours
737:11 is the ratio of distance to time
so the other ratio we have is
603:x, x is missing
we assume the ratios to be equal so
737:11=603:x
fractionify
737/11=603/x
multiply both sides by 11x
737x=6633
divide both sides by 737
x=9

answer is 9 houurs

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Put the equation in standard linear form.

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$\mu = \exp\left(\displaystyle \int \frac{dt}{t+5}\right) = e^{\ln|t+5|} = t+5$

Multiply both sides by $\mu$ .

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Now the left side the derivative of a product,

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Integrate both sides.

$(t+5) x(t) = \displaystyle 5 \int (t+5) e^{5t} \, dt$

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$(t+5) x(t) = \dfrac15 (5t+24) e^{5t} + C$

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1 year ago

Simplify 7/8 divided by 8

meriva

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Step-by-step explanation:

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3 years ago

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3 years ago

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respectively, with $0\le t\le1$ , where $\mathbf r_i(t)=(x(t),y(t))$ .

We have

$\mathrm d\mathbf r_1=(6,1)\,\mathrm dt$

$\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt$

where $\mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt$

so the line integral becomes

$\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)$

$=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt$

$=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6$

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2 years ago