Answer:
680 sales
Step-by-step explanation:
20% of 680 is 136.
So her 64 for a week plus the 136 from sales is 200.
Hope this helps
Brainliest would be appreciated
Answer:
The system has no solutions
Step-by-step explanation:
we have
-----> equation A
----> equation B
Isolate the variable y in the equation A
![5y=4x-5](https://tex.z-dn.net/?f=5y%3D4x-5)
![y=\frac{4}{5}x-1](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B4%7D%7B5%7Dx-1)
-----> equation A'
Isolate the variable y in equation B
![0.10y=0.08x+0.10](https://tex.z-dn.net/?f=0.10y%3D0.08x%2B0.10)
![y=\frac{0.08}{0.10}x+1](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B0.08%7D%7B0.10%7Dx%2B1)
------> equation B'
Compare the equations A' and B'
The lines have the same slope but different y-intercept
Are parallel lines
therefore
The system has no solutions
The clock will tell you the time of how long it will take
Trigonometric Identities.
To solve this problem, we need to keep in mind the following:
* The tangent function is negative in the quadrant II
* The cosine (and therefore the secant) function is negative in the quadrant II
* The tangent and the secant of any angle are related by the equation:
![\sec ^2\theta=\tan ^2\theta+1](https://tex.z-dn.net/?f=%5Csec%20%5E2%5Ctheta%3D%5Ctan%20%5E2%5Ctheta%2B1)
We are given:
![\text{tan}\theta=-\frac{\sqrt[]{14}}{4}](https://tex.z-dn.net/?f=%5Ctext%7Btan%7D%5Ctheta%3D-%5Cfrac%7B%5Csqrt%5B%5D%7B14%7D%7D%7B4%7D)
And θ lies in the quadrant Ii.
Substituting in the identity:
![\begin{gathered} \sec ^2\theta=(-\frac{\sqrt[]{14}}{4})^2+1 \\ \text{Operating:} \\ \sec ^2\theta=\frac{14}{16}+1 \\ \sec ^2\theta=\frac{14+16}{16} \\ \sec ^2\theta=\frac{30}{16} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Csec%20%5E2%5Ctheta%3D%28-%5Cfrac%7B%5Csqrt%5B%5D%7B14%7D%7D%7B4%7D%29%5E2%2B1%20%5C%5C%20%5Ctext%7BOperating%3A%7D%20%5C%5C%20%5Csec%20%5E2%5Ctheta%3D%5Cfrac%7B14%7D%7B16%7D%2B1%20%5C%5C%20%5Csec%20%5E2%5Ctheta%3D%5Cfrac%7B14%2B16%7D%7B16%7D%20%5C%5C%20%5Csec%20%5E2%5Ctheta%3D%5Cfrac%7B30%7D%7B16%7D%20%5Cend%7Bgathered%7D)
Taking the square root and writing the negative sign for the secant: