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jok3333 [9.3K]
2 years ago
7

I need all of these please help someone

Mathematics
2 answers:
Fudgin [204]2 years ago
5 0
Ok so i only did 9-18
the circles are the questions and the answers are boxed in, sorry if they are not right i tried my best to help u out

EleoNora [17]2 years ago
5 0
If u ever need more help download this app called Photomath u scan the equation and it gives u the answer and if you don’t wanna scam it u can type it in using the calculator it lets u add and, subtract, multiply, and divide fractions
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Name ____________________________ Class________ Date ____________________________ Directions: Each diagram is formed by two para
hodyreva [135]

Step-by-step explanation:

How are we supposed to help...?

3 0
3 years ago
What is the answer to this question please explain (picture included)
Yakvenalex [24]
Easy peasy
just use PEMDAS and some exonential laws

(x^{m})(x^{n})=x^{m+n}
(x^{m})^{n}=x^{mn}
(ab)^{m}=(a^{m})(b^{m})

also another is x^{\frac{m}{n}}=\sqrt[n]{x^{m}}

so

[3(2a)^{\frac{3}{2}}]^{2}=
(3^{2})((2a)^{\frac{3}{2}}^{2})=
(9)((2a)^{\frac{3}{2}}^{2})=
(9)((2a)^{\frac{6}{2})=
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72a^{3}

3 0
3 years ago
How do I do 3 x 10^5
Ilya [14]

Answer: 3(10^5)

=3*10^5

=3*(10*10*10*10*10)

=300000

This is how you should do It, just when it is squared you should times the number like up here you times 10 times 10 5 times so if you see it you don't times it by 5 you do 10 times 10 times 10 times 10 times 10 like this

You should get it now

Have a good day

Yours,

Nathaniel

Step-by-step explanation:

4 0
2 years ago
At a farmers market you buy 4 pounds of toamtoes(3$ each) and 2 pounds of sweet potatoes (2$ each). You spend 80% of he money in
Artyom0805 [142]
4*3=12
2*2=4
12+4=16
16/4=4
4*5=20
Therefore, $20 was the original amount of money in your wallet.
7 0
3 years ago
Find the limit if it exists lim x→0 sqrtx+7-sqrt7 over x
Triss [41]

Answer:

\frac{1}{ 2\sqrt{7} }

Step-by-step explanation:

\lim_{x\to 0}  \frac{ \sqrt{x + 7}  -  \sqrt{7} }{x}  \\  \\  = \lim_{x\to 0}  \frac{( \sqrt{x + 7}  -  \sqrt{7}) }{x}  \times  \frac{( \sqrt{x + 7}   +   \sqrt{7}) }{( \sqrt{x + 7}   +  \sqrt{7}) }  \\  \\   = \lim_{x\to 0}  \frac{( \sqrt{x + 7} )^{2}  -  (\sqrt{7})^{2}  }{x( \sqrt{x + 7}   +  \sqrt{7})}  \\  \\   = \lim_{x\to 0}  \frac{( {x + 7}  -  {7}) }{x( \sqrt{x + 7}   +  \sqrt{7})}   \\  \\ = \lim_{x\to 0}  \frac{ {\cancel x}}{\cancel x( \sqrt{x + 7}   +  \sqrt{7})} \\  \\ = \lim_{x\to 0}  \frac{ {1}}{\sqrt{x + 7}   +  \sqrt{7}}  \\  \\  =  \frac{1}{ \sqrt{0 + 7} +  \sqrt{7}  } \\  \\  =  \frac{1}{ \sqrt{7} +  \sqrt{7}  }  \\  \\  =  \frac{1}{ 2\sqrt{7} }

6 0
3 years ago
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