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3 years ago

Can someone help me with this question

Mathematics

1 answer:

prisoha [69]3 years ago

4 0

Answer:

0 0 0 0 0 or

1 2 2 2 3

Step-by-step explanation:

These satisfy all requirements.

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09.04 Continuity at a point Find the indicated limit, if it exists. (2 points)

LenKa [72]

Answer:

Step-by-step explanation:

limit is defined when the limit from both side are defined and equal to f

$x-> -10^-$ , limit f(x)=-4-(-10)=6

f(-10)=6

$x-> -10^+$ , limit f(x)=(-10)+16=6

Then

$x->-10$ , limit f(x)=6

6 0

2 years ago

Simplify 14 to the 15th power over 14 to the 5th power.

cluponka [151]

14^15/14^5=14^(15-5)=14^10

Hope this kinda helps !!

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3 years ago

Find the minimum or maximum value of the function. What is the H? (Desmos)

beks73 [17]

Answer:

Minimum: (2,4)

Step-by-step explanation:

h(x)=3( $x^{2}$ -4x)+16

=3( $x^{2}$ -4x+4-4)+16 (- For the balance of equation, and attention 1)

=3 $(x-2)^{2}$ -3*4+16

=3 $(x-2)^{2}$ +4

<h3>Attention:</h3>

1. $(a-b)^{2}=a^{2} -2ab+b^{2}$

2. The formula for the vertex form is y = $a(x-h)^{2}+k$ , the vertex is (h,k)

4 0

2 years ago

What is the equation of the line that passes through the point (6,14) and is parallel to the line with the following equation? y

Gekata [30.6K]

Answer:

$y=\displaystyle-\frac{4}{3}x+22$

Step-by-step explanation:

Hi there!

What we need to know:

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept
Parallel lines always have the same slope (m)

Determine the slope (m):

$y=\displaystyle-\frac{4}{3}x -1$

The slope of the given line is $\displaystyle-\frac{4}{3}$ , since it is in the place of m in y=mx+b. Because parallel lines always have the same slope, the slope of a parallel line would also be $\displaystyle-\frac{4}{3}$ . Plug this into y=mx+b: