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Agata [3.3K]
3 years ago
9

Select ALL the correct answers. Select all the expressions that are equivalent to the polynomial below. (4x+5)(-3x-1)

Mathematics
1 answer:
AfilCa [17]3 years ago
4 0
The answers are:
 A. (-16x²+10x-3)+(4x²<span>-29x-2)
</span> C. 2(x-1)-3(4x²+7x+1)
 D. (2x²-11x-9)-(14x²+8x-4)
 The explanation is shown below:
 1- When you apply the distributive property to the polynomial <span>(4x+5)(-3x-1), you obtain the following form:
</span> -12x²-19x-5
 2- If you apply the same property to the polynomials shown in the options above and add the terms with equal exponents, you will obtain that the polynomials that has the same form are:
 A. (-16x²+10x-3)+(4x²-29x-2):
 -16x²+10x-3+4x²-29x-2
 -12x²-19x-5
 C. 2(x-1)-3(4x²+7x+1)
 2x-2-12x²-21x-3
 -12x²-19x-5
 D. (2x²-11x-9)-(14x²+8x-4)
 2x²-11x-9-14x²-8x+4
 -12x²-19x-5  
 
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A fair coin and a biased coin where the probability of obtaining a head is twice the probability of obtaining a tail. if both ar
Art [367]

Answer:

See below in bold.

Step-by-step explanation:

For the fair coin Prob(head) = 1/2 and Prob(Tail) = 1/2.

For the biased coin it is   Prob(head) = 2/3 and Prob(Tail) = 1/3.

a) Prob(2 heads) = 1/2 * 2/3 = 1/3.

b) Prob(2 tails) = 1/2 * 1/3 = 1/6.

c) Prob(1 head ) = Prob(H T or T H) = 1/2 * 1/3  + 1/2 * 2/3) = 1/6+1/3 = 1/2.

d) Prob (at least one head) = prob (HH or TH or HT) =  1/3 + 1/2 =<em> </em>5/6.

4 0
3 years ago
4−3(x−5)&gt;6x−17 Given
Alex777 [14]

Answer:

Answer

Step-by-step explanation:


4 0
3 years ago
Which triangles are similar by the angle-angle criterion for similarity of triangles ?
Alex Ar [27]

Answer:

Option D is correct.

\triangle ADE \sim \triangle ABC

Step-by-step explanation:

In triangle ADE and triangle ABC

From the figure:

\angle ADE = \angle ABE  [Angle]             [Given]

\angle DAE = \angle BAC  [Angle]

AA(Angle-Angle) similarity criterion states that in two triangles if two pairs of corresponding angles are equal, then these triangle Similar.

By AA similarity:

⇒\triangle ADE \sim \triangle ABC

5 0
3 years ago
Please see the image and help with this homework problem. thank you!
dimulka [17.4K]

we have the function

E=\sin \frac{\pi}{14}t

Part a

For t=7

substitute in the given function

\begin{gathered} E=\sin \frac{\pi}{14}7 \\ E=1 \end{gathered}

For t=14

\begin{gathered} E=\sin \frac{\pi}{14}14 \\ E=0 \end{gathered}

For t=21

\begin{gathered} E=\sin \frac{\pi}{14}21 \\ E=-1 \end{gathered}

For t=28

\begin{gathered} E=\sin \frac{\pi}{14}28 \\ E=0 \end{gathered}

For t=35

\begin{gathered} E=\sin \frac{\pi}{14}35 \\ E=1 \end{gathered}

Observation: The values of E varies from -1 to 1, including the zero

Part B

Remember that

The Period goes from one peak to the next

so

Period=2pi/B

B=pi/14

Period=(2pi)/(pi/14)=2pi*14/pi=28

<h2>the period is 28 days</h2>
6 0
1 year ago
5(3 – x) &lt; -2x + 6,<br> Please help
svetlana [45]

Answer:

9<7x

Step-by-step explanation:

5(3-x) < -2x+6

15-5x<-2x+6

9<7x

then you can simplify it if you want

3 0
3 years ago
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