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sertanlavr [38]
3 years ago
12

Give me example of a unit rate used in real life

Mathematics
1 answer:
lana66690 [7]3 years ago
3 0

Before you begin this lesson, please print the accompanying document, Unit Rates in Everyday Life].

Have you ever been at the grocery store and stood, staring, at two different sizes of the same item wondering which one is the better deal? If so, you are not alone. A UNIT RATE could help you out when this happens and make your purchasing decision an easy one.

In this lesson, you will learn what UNIT RATES are and how to apply them in everyday comparison situations. Click the links below and complete the appropriate sections of the Unit Rates handout.

[Note: The links below were created using the Livescribe Pulse Smartpen. If you have never watched Livescribe media before, take a few minutes to watch this very brief Livescribe orientation]

<span>What is a UNIT RATE – definitionView some examples of Unit RatesSee a process to compute Unit Rates</span>
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Factor expression. Show your work. q^2 - 9 = (q + 3)(g - 3)
lys-0071 [83]
We have
<span>q^2 - 9 = (q + 3)(g - 3)

</span>q^2 - 9---------------> (q+3)(q-3)
therefore
(q+3)(q-3)=(q + 3)(g - 3)
(q-3)=(g - 3)
q=g
4 0
3 years ago
max is 24 years older than his son liam in two years liam will be half as old as max how old is liam now
sertanlavr [38]
Max is 26 now because 24 + 2 = 26 so 26 / 2 = 13

Liam is 13.

I hope this helps :)

5 0
3 years ago
Read 2 more answers
1. What is the slope and how is it determined from a g raph?
Goryan [66]

Answer:

The<u> rise divided by the run </u>is the slope of a line. The rise and run are used to estimate the slope of a line from its graph.

To determine the intercepts from a graph,  We <u>put y equal to zero</u> and solve for x to find the x-intercept. Similarly, we put x equal to zero and solve for y to find the y-intercept.

6 0
3 years ago
Given m = 3/2 and the point (0, -6), which of the following is the point-slope form of the equation?
Aleks04 [339]

Answer:

Step-by-step explanation:

The equation of a line in

point-slope form

is.

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

∣

∣

∣

2

2

y

−

y

1

=

m

(

x

−

x

1

)

2

2

∣

∣

∣

−−−−−−−−−−−−−−−−−−−−−−

where m represents the slope and

(

x

1

,

y

1

)

a point on the line

here

m

=

−

2

and

(

x

1

,

y

1

)

=

(

3

,

0

)

⇒

y

−

0

=

−

2

(

x

−

3

)

⇒

y

=

−

2

(

x

−

3

)

←

in point-slope form

8 0
3 years ago
I need help finding both volume and surface area
Svetradugi [14.3K]

Answer:

<u>Volume</u>

For the rectangle, h = 3cm, l = 8cm, w = 6cm
V = length x width x height
V = 8cm x 6cm x 3cm
V = 144cm^3

For the semi circle, we need to find the radius. The radius is width/2, so 6cm/2 = 3cm. r = 3cm, \pi = 3.14
V = radius^2 x height x \pi
V = 3cm^2 x 3cm x 3.14
V = 84.8 cm^3/2 (because the cylinder needs to be divided to form a semi-circle)
V= 42.4cm^3 (there are two cylinders though so we will multiply this by 2 in the total volume)

Total volume:
V = 144cm^3 + 42.4cm^3(2)
V = 186.4cm^3

<u>Surface Area</u>

Rectangular prism:
A = 2[w(l) + h(l) + h(w)]
A = 2[6cm(8cm) + 3cm(8cm) + 3cm(6cm)]
A = 180cm^2
But there are two sides that are covered by the semi-circular prisms, so we will have to calculate those sides and remove them.
A = l x w
A = 6cm x 3cm
A = 18cm^2(2) (2 being the two faces)
A = 36cm^2

A = 180cm^2 - 36cm^2
A = 144cm^2 (the area of the rectangle)

Semi-circular prism:
A = 2\pirh + 2\pir^2
Earlier, we found out that the radius of the circle is 3cm, so we will plug that in.
A = 2(3.14)(3cm)(3cm) + 2(3.14)(3cm)^2
A = 113.09cm^2

Total surface area:
A = 144cm^2 + 133.09cm^2
A = 277.09cm^2

Therefore the total volume of the prism is 186.4cm^3 and the total surface area is 277.09cm^2.





6 0
2 years ago
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