Please find h step by step

Mathematics

1 answer:

soldier1979 [14.2K]3 years ago

3 0

it should be 1.6 hope that helps you

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Use the picture for the question and the answer choices:)

Orlov [11]

Parenthesis first 5-2=3.

7^2=49

-3*3=-9

49-9=40.

A is your answer.

8 0

3 years ago

A mass weighing 3 lb stretches a spring 3 in. If the mass is pushed upward, contracting the spring a distance of 1 in and then s

Bas_tet [7]

Answer:

Step-by-step explanation:

$m=\frac{3}{32}\\ \gamma =0\text{ damping constant.}\\ k=\frac{3}{\frac{1}{4}}=12\\ F(t)=0\\ \text{so equation of motion is }\\ mu''+\gamma u'+ku=F(t)\\ \frac{3u''}{32}+12u=0\\ u''+128u=0\\ \text{and initial conditions are}\\ u(0)=-\frac{1}{12}\\ u'(0)=2\\ u''+128u=0\\ \text{characterstic equation is}\\ r^2+128=0\\ \text{roots are }\\ r=\pm 8\sqrt{2}i\\ \text{therefore general solution is}\\ u(t)=A\cos8\sqrt{2}t+Bsin8\sqrt{2}t\\ \text{using initial conditions we get}\\ A=-\frac{1}{12}\\ B=\frac{\sqrt{2}}{8}\\ \text{therefore solution is }\\ u(t)=-\frac{1}{12}\cos8\sqrt{2}t+\frac{\sqrt{2}}{8}\sin8\sqrt{2}t\\
{hence}\\R=\sqrt{\frac{11}{288}}\\\\\sigma=\pi - \tan^{-1}\frac{1}{\sqrt{2}}\\\\\omega_0=8\sqrt{2}\\T=\frac{4}{4\sqrt{2}}$

3 0

3 years ago

What is One + One?????????

pychu [463]

Answer:

one plus one is two the answer is 2

4 0

3 years ago

Read 2 more answers

Just welp me finish this math stuff pls

kykrilka [37]

Answer:

2/7

Step-by-step explanation:

You would add what is in the parenthesees and you get 6/14 and if you simplify you get 3/7. So you would do 5/7 -3/7

8 0

3 years ago

Read 2 more answers

A cone and a cylinder have the same height and their bases are congruent circles

Anettt [7]

Answer:

$30cm^3$

Step-by-step explanation:

the volume of a cylinder is given by:

$v_{cylinder}=\pi r^2 h$

and the volume of a cone is given by:

$v_{cone}=\frac{\pi r^2 h}{3}$

since both have the same height and radius, we can solve each equation for $r^2h$ (because this quantity is the same in both figures) and then match the expressions we find: