The domain is the x-axis and the range is the y-axis.
To find the domain, you measure or count the widest part of this oval horizontally. So that is 3 units to the right of 0 and 3 units to the left of 0. I counted it exactly on the axis because that is the widest part of the oval.
To find the range, you again count or measure the widest part of the oval vertically. So that is 4 units above 0 and 4 units below 0.
<u>Final Answer</u>
D: -3 ≤ x ≤ 3
R: -4 ≤ x ≤4
Answer:
(a) 4
(b) 2√3
(c) 60°
(d) 120°
Step-by-step explanation:
(a) The relationship between tangents and secants is ...
CB^2 = CD·CA
Filling in the given values, we find ...
CB^2 = 2·(2+6) = 16
CB = √16 = 4
The length of BC is 4 units.
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(b) Triangle ABC is a right triangle, so the sides of it satisfy the Pythagorean theorem.
CA^2 = CB^2 +AB^2
8^2 = 16 +AB^2
AB = √48 = 4√3
The radius is half the length of AB, so the radius is 2√3.
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(c) The measure of angle C can be determined from the cosine relation:
cos(C) = CB/CA = 4/8 = 1/2
C = arccos(1/2) = 60°
The measure of angle C is 60°.
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(d) Arc AD is intercepted by angle ABD, which has the same measure as angle C. Hence the measure of arc AD is twice the measure of angle C.
The measure of arc AD is 120°.
-3x=2x+19
-19 -19
-3x-19=2x
+3x +3x
-19=5x
/5 /5
x=19/5
Answer:
-11/8
Step-by-step explanation:
-7/8 - 1/2 = -11/8
Answer:
Step-by-step explanation:
= Mass flow rate of water = 320 kg/s
= Mass of water on the door
= Time
= Velocity of water on the door = 20 m/s
Force is given by
The average force is exerted by the stream of water is .
