Question

Consider the radical equation = c + 2. Which statement is true about the solutions c = 3 and c = –6?

Answer 1

The inside of the radical must be greater than or equal to zero. When you plug in c=3, the answer is 5 >0. When c=-6, -4 <0. Therefore c=3 is true.

Answer 2

Answer:

c = 3

Step-by-step explanation:

the expression is $\sqrt{c+2}$

Substitute, 3 for c, we get the value of expression is $\sqrt{5}$

This value is possible because the square root is defined for positive values.

Substitute, - 6 for c, we get the value of expression is $\sqrt{-5+2}$

This value is not possible because the square root of negative value sis not defined.

So, c = 3 is true for the given expression.