All categories

3 years ago

Which of the following is equivalent to four raised to the power of negative two.?

Mathematics

1 answer:

AfilCa [17]3 years ago

5 0

To raise a number n to a negative power you simply take the fraction 1/n and raise it to the (positive) power you want.

${n}^{ - m} = { \frac{1}{n} }^{m}$

So 2^-2 is ¼.

You might be interested in

One year, the Sahara Desert received 0.98 inches of rain. That same year the rain forest in Brazil received 342 inches. How much

lisabon 2012 [21]

Answer:

Step-by-step explanation:

Gjgxgioilgghgjkhvyuguyykuyl

3 0

3 years ago

a biologist counted 15 squirrels in 3 acres of forest. based on that data how many squirrels would be expected yo inhabit a 275

VLD [36.1K]

Answer:

Step-by-step explanation:

275/3=91.6 recurring

91.6 recurring x 15= 1375

8 0

4 years ago

If you park 3 levels below the lobby floor of a hotel and take the elevator to the 15th floor, how many floors apart are you fro

klio [65]

So the lobby would be the 1st floor, and the level you parked your car on would be the -3rd level.

15+3 would be 18. So you are 18 levels away from your car

8 0

4 years ago

Read 2 more answers

WHAT IS (2x2A5)x35= please answer

Anna71 [15]

The answer is 140x^5

4 0

4 years ago

Dullco Manufacturing claims that its alkaline batteries last at least 40 hours on average in a certain type of portable CD playe

Gennadij [26K]

Answer:

$p_v =P(t_{17}$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

The best option for this case would be:

We would switch to α = .01 for a more powerful test.

Step-by-step explanation:

Previous concepts and data given

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=37.8$ represent the sample mean

$s=5.4$ represent the sample standard deviation

n=18 represent the sample selected

$\alpha=0.05$ significance level

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is less than 40, the system of hypothesis would be:

Null hypothesis: $\mu \geq 40$

Alternative hypothesis: $\mu < 40$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{37.8-40}{\frac{5.4}{\sqrt{18}}}=-1.728$

P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=18-1=17$

Since is a left tailed test the p value would be:

$p_v =P(t_{17}$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

The best option for this case would be:

We would switch to α = .01 for a more powerful test.

Since the p values is just a little higher than th significance level 0.051>0.05 but the values are two close. If we change the value of the significance by 0.01, we have that 0.051>0.01 and it's a more powerful test.

4 0

3 years ago