Answer:
The terminal point is Q(0,4)
Step-by-step explanation:
We are given the following in the question:
Initial point of vector, P(1,0)
The terminal point Q lies on the y-axis, thus Q have coordinates of the form:
The magnitude of the vector is 
Magnitude is given by:
But since the terminal point is above the initial point, thus,
Thus, the terminal point is Q(0,4)
Answer:
the answer is 15 I just took the assessment
Answer:
y = 0x + 2
Step-by-step explanation:
Find the slope.
Slope = <u> y2 - y1</u>
x2 - x1
Plug in the points.
Slope = <u>2 - 2</u> = <u>0</u>
-7 - 8 -15
Pick a point to plug into the y = mx + b formula
I picked (8,2)
Now plug in the point and slope.
(Your teacher might prefer you to use 0/-17, but it can be simplified to 0, so I'll just use that.)
Equation: (2) = 0(8) + b
2 = 0 + b
2 = b (b = 2)
Now put your slope and the y-intercept into the equation, and it will be:
y = 0x + 2
It's a bit hard to show on keyboard, so I hope you understand.
Answer:
p=-30
Step-by-step explanation:
p+12=-18
subtract 12 on both sides and you get p=-30
Hope this helps!!
