What is the complete factorization of the polynomial function over the set of complex numbers?
2 answers:
Answer:
f(x)=(x-2)(x+2)(x-5)
Step-by-step explanation:
f(x)=x³-5x²+4x-20 1. Just group randomly
f(x)=x²(x-5)+4(x-5) 2. Factor the groupings
f(x)=(x²+4)(x-5)
<u>f(x)=(x-2)(x+2)(x-5)</u> 3. Factor the difference of two squares
Answer:
is the required factorization of f(x).
Step-by-step explanation:
To factor the expression we must first group the terms and then take out common from these groups

Taking
common from first group and the 4 from second group we get:

Now, to factor in complex from we have to break term 

As, 
Also using identity 
On solving

is the required factorization of f(x).
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Answer:
12 + -6i
a=12
b=-6
Step-by-step explanation:
( -4 + 3i ) ( -3 - 2i )
-4 * -3 = 12
3i * -2i= -6i
12 + -6i
Answer: 2.45346638e+19
Step-by-step explanation:
2 consecutive even integers : x and x + 2
4(x) + 3(x + 2) = 20
4x + 3x + 6 = 20
7x + 6 = 20
7x = 20 - 6
7x = 14
x = 14/7
x = 2
x + 2 = 2 + 2 = 4
so ur first number (x) = 2 and ur second number (x + 2) = 4
The slope of the line is
y = -2