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nirvana33 [79]
3 years ago
8

Enrico waited ten years to file a cause of action against Frederico for a breach of contract claim. Frederico can use ______ as

his defense.
Computers and Technology
1 answer:
ser-zykov [4K]3 years ago
3 0
Time, due to the amount of time between the initial action and the filing of the report, federico could claim the it didn't happen or something
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Assume the existence of a Bank Account class. Define a subclass, Savings Account that contains the following: a double instance
Finger [1]

The solution is in the attachment

5 0
3 years ago
Write a program that reads numbers from a file (or allow user to input data) and creates an ordered binary tree. The program sho
IgorLugansk [536]

Answer:

See explaination

Explanation:

include<bits/stdc++.h>

using namespace std;

typedef struct Node

{

int data;

struct Node *left,*right;

}Node;

bool search(Node *root,int data)

{

if(root==NULL)

return false;

if(root->data==data)

return true;

queue<Node*> q;

q.push(root);

while(!q.empty())

{

Node *temp=q.front();

q.pop();

if(temp->data==data)

return true;

if(temp->left)

q.push(temp->left);

if(temp->right)

q.push(temp->right);

}

return false;

}

Node *insert(Node *root,int data)

{

if(root==NULL)

{

Node *temp=new Node();

temp->data=data;

temp->left=NULL;

temp->right=NULL;

return temp;

}

if(data < root->data)

root->left=insert(root->left,data);

if(data>root->data)

root->right=insert(root->right,data);

return root;

}

Node *get_smallest_element_right_subtree(Node *root)

{

while(root && root->left!=NULL)

root=root->left;

return root;

}

Node *delete_node(Node *root,int data)

{

if(root==NULL)

return root;

if(data < root->data)

root->left=delete_node(root->left,data);

else if(data > root->data)

root->right=delete_node(root->right,data);

else

{

if(root->left==NULL) //If right only presents means - delete the curr node and return right node

{

Node *temp=root->right;

free(root);

return temp;

}

else if(root->right==NULL) //If left only presents means - delete the curr node and return let node

{

Node *temp=root->left;

free(root);

return temp;

}

else

{

Node *temp=get_smallest_element_right_subtree(root->right);

root->data=temp->data;

root->right=delete_node(root->right,temp->data);

}

return root;

}

}

void inorder(Node *root)

{

if(root!=NULL)

{

inorder(root->left);

cout<<root->data<<" ";

inorder(root->right);

}

}

void postorder(Node *root)

{

if(root!=NULL)

{

inorder(root->left);

inorder(root->right);

cout<<root->data<<" ";

}

}

void preorder(Node *root)

{

if(root!=NULL)

{

cout<<root->data<<" ";

inorder(root->left);

inorder(root->right);

}

}

int main()

{

fstream f;

string filename;

cout<<"\n\n1 - Input through File ";

cout<<"\n\n2 - Input through your Hand";

int h;

cout<<"\n\n\nEnter Your Choice : ";

cin>>h;

Node *root=NULL; // Tree Declaration

if(h==1)

{

cout<<"\n\nEnter the Input File Name : ";

cin>>filename;

f.open(filename.c_str());

if(!f)

cout<<"\n\nError in Opening a file !";

else

{

cout<<"\n\nFile is Being Read ........";

string num;

int value;

int node=0;

while(f>> num)

{

value=stoi(num);

root=insert(root,value);

node++;

}

cout<<"\n\nTree has been successfully created with : "<<node<<" Nodes"<<endl;

}

}

if(h==2)

{

int y;

cout<<"\n\nEnter the Total No of Input :";

cin>>y;

int i=1,g;

while(i!=y+1)

{

cout<<"\n\nEnter Input "<<i<<" : ";

cin>>g;

root=insert(root,g);

i++;

}

cout<<"\n\nTree has been successfully created with : "<<y<<" Nodes"<<endl;

}

if(h>=3)

{

cout<<"\n\nInvalid Choice !!! ";

return 0;

}

int n=0;

while(n!=6)

{

cout<<"\n\n\n1 - Insert Element";

cout<<"\n\n2 - Remove Element";

cout<<"\n\n3 - Inorder (LNR) Display ";

cout<<"\n\n4 - Pre (NLR) Order Display";

cout<<"\n\n5 - Post (LRN) Order Display";

cout<<"\n\n6 - Quit";

cout<<"\n\nEnter Your Choice : ";

cin>>n;

switch(n)

{

case 1:

{

int k;

cout<<"\n\nEnter Element to insert : ";cin>>k;

root=insert(root,k);

cout<<"\n\nElement Sucessfully Inserted !!!!!";

break;

}

case 2:

{

int k;

cout<<"\n\nEnter Element to Remove : ";

cin>>k;

if(search(root,k))

{

root=delete_node(root,k);

cout<<"\n\nValue Successfully Deleted !!!";

}

else

cout<<"\n\n!!!!!!!!!!!!!!!!!!!! No Such Element !!!!!!!!!!!!!!!!!!!!!!";

break;

}

case 3:

{

cout<<"\n\nThe Elements (LNR) are : ";

inorder(root);

break;

}

case 4:

{

cout<<"\n\nThe Elements (NLR) are : ";

preorder(root);

break;

}

case 5:

{

cout<<"\n\nThe Elements (LRN) are : ";

postorder(root);

break;

}

case 6:

{

break;

}

}

}

cout<<"\n\nBye!!!! See You !!!"<<endl;

7 0
3 years ago
The only requirement of __________ is that the sender must provide some mechanism whereby the receiver can opt out of future ema
fiasKO [112]

Answer:

The CAN-SPAM Act

Explanation:

Email or electronic mail is an information system mechanism of communication, that involves the use of digital devices to initiate communication over the internet. The email uses several protocols like the POP3, IMAP etc.

The CAN-SPAM Act is proposed in the United States law, applicable to email investigations. It requires that a sender provides a mechanism whereby the receiver can opt out of future emails without a fee.

4 0
2 years ago
What is the maximum number of VLANs that can be configured on a switch supporting the 802.1Q protocol? Why?
KATRIN_1 [288]

Answer:

Under IEEE 802.1Q, the maximum number of VLANs on a given Ethernet network is 4,094 (4,096 values provided by the 12-bit VID field minus reserved values at each end of the range, 0 and 4,095).

Explanation: found it from google

6 0
2 years ago
Read 2 more answers
Write a loop that subtracts 1 from each element in lowerScores. If the element was already 0 or negative, assign 0 to the elemen
Verdich [7]

Answer:

Replace <STUDENT CODE> with

for (i = 0; i < SCORES_SIZE; ++i) {

       if(lowerScores.at(i)<=0){

           lowerScores.at(i) = 0;

       }

       else{

           lowerScores.at(i) = lowerScores.at(i) - 1;

       }  

   }

Explanation:

To do this, we simply iterate through the vector.

For each item in the vector, we run a check if it is less than 1 (i.e. 0 or negative).

If yes, the vector item is set to 0

If otherwise, 1 is subtracted from that vector item

This line iterates through the vector

for (i = 0; i < SCORES_SIZE; ++i) {

This checks if vector item is less than 1

       if(lowerScores.at(i)<1){

If yes, the vector item is set to 0

           lowerScores.at(i) = 0;

       }

       else{

If otherwise, 1 is subtracted from the vector item

           lowerScores.at(i) = lowerScores.at(i) - 1;

       }  

   }

Also, include the following at the beginning of the program:

<em>#include <vector></em>

8 0
2 years ago
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