They are: translation, dilation.
Answer:
(a) A = 700×1.015^t
(b) 36.2 years
Step-by-step explanation:
(a) Each year, the account value is multiplied by (1 + 1.5%) = 1.015. Repeated multiplication is signified using an exponent. In t years, when the account has been multiplied by 1.015 t times, the account value will be ...
A = $700×1.015^t
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(b) You want to find t when A=$1200. Logarithms are involved.
1200 = 700×1.015^t . . . . use 1200 for A
1200/700 = 1.015^t . . . . . divide by 700
log(12/7) = t×log(1.015) . . . . . take logarithms
log(12/7)/log(1.015) = t ≈ 36.2 . . . . divide by the coefficient of t
It will take about 36.2 years for the account balance to reach $1200.
Answer:
Step-by-step explanation:
Given that:
The numbers of the possible public swimming pools are 5
From past results, we have 0.007 probability of finding bacteria in a public swimming area.
In the public swimming pool, the probability of not finding bacteria = 1 - 0.007
= 0.993
Thus;
Probability of combined = Probability that at least one public
sample with bacteria swimming area have bacteria
Probability of combined sample with bacteria = 1 - P(none out of 5 has
bacteria)
Probability of combined sample with bacteria = 1 - (0.993)⁵
= 1 - 0.9655
= 0.0345
Thus, the probability that the combined sample from five public swimming areas will show the presence of bacteria is 0.0345
From above, the probability that the combined sample shows the presence of bacteria is 0.0345 which is lesser than 0.05.
Thus, we can conclude that; Yes, the probability is low enough that there is a need for further testing.
Answer:
B.
Step-by-step explanation:
I have attached the work to your problem.
Please see the attachment below.
I hope this helps!
