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3 years ago

Graph y=1/4x-6 Use the line tool and select two points on the line

Mathematics

1 answer:

DochEvi [55]3 years ago

7 0

Answer:

2 points would be 10 and -10

Step-by-step explanation:

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A state offers two lottery games, WinOne and PlayBall. Both games cost $2 per ticket.

uysha [10]

In this question, both tickets cost 2$ per ticket.
The answer to this question would be: $0

In WinOne scenario, you need to match a ticket that has to pick from A-J(10 possibilities) and 0-9 (10 possibilities). The chance to win would be: 1/10* 1/10= 1/100

The expected value must be:
E= chance to win * win amount - ticket price
E= 1//100*$200 - $2= $2-$2= 0

8 0

2 years ago

Help me plzzzzzzz thx

Anna [14]

It's just one, if there isn't any other number attached to the x^2 you can just assume the leading coefficient is 1

6 0

2 years ago

A bakery sells mocha cupcakes and chocolate cupcakes. It sold 220 cupcakes in a day, and 45% of them were chocolate. How many of

Inessa05 [86]

Answer:

121 mocha cupcakes

Step-by-step explanation:

$\frac{45}{100} \times 220 = 99 \\ 99of \: the \: cupcakes \: were \: chocolate \\ mocha \: cupcakes = 220 - 99 \\ = 121$

6 0

2 years ago

What's the capital city of South Sudan

Effectus [21]

Answer:

juba

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

Colt1911 [192]

Answer: 34%

Step-by-step explanation:

According to the Empirical rule,

About 68% of the population lies with in one standard deviation from the mean.

i.e. About 34% of the population lies above one standard deviation from the mean .

and About 34% of the population lies below one standard deviation from the mean.

Given : The distribution of the number of daily requests is bell-shaped ( i.e. Normally distribution) and has a mean of 60 and a standard deviation of 11.

i.e. $\mu=60\ \ \sigma=11$

Using the Empirical Rule rule, 34% of the population of lightbulb replacement requests lies above one standard deviation from the mean .

i.e. About 34% of the population of lightbulb replacement requests lies between $\mu$ and $\mu+\sigma$

i.e. About 34% of the population of lightbulb replacement requests lies between $60$ and $60+11$

i.e. About 34% of the population of lightbulb replacement requests lies between 60 and 71

Hence, the approximate percentage of lightbulb replacement requests numbering between 60 and 71 = 34%

4 0

2 years ago