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3 years ago

If the factors of quadratic function g are (x-7) and (x + 3), what are the zeros of function g?

Mathematics

2 answers:

KATRIN_1 [288]3 years ago

7 0

Answer:

Option d is answer

Step-by-step explanation:

study about algebra

galina1969 [7]3 years ago

6 0

Is a b c or d

The question

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Use a coordinate grid to plot the points (—2, 3) and (4, 5) then plot two more points so that all four points form vértices of a

musickatia [10]

Answer:

The answer to your question is below

Step-by-step explanation:

See the picture below

Data

A (-2, 3)

B (4, 5)

I plotted the points C (4, 3) and D (-2, 5)

Distance

dAC = $\sqrt{(4 + 2)^{2}+ (3-3)^{2}}$

= $\sqrt{(6)^{2}}$

= 6

dBD = $\sqrt{(4 + 2)^{2}+ (5 - 5)^{2}}$

= $\sqrt{36}$

= 6

dAD = $\sqrt{(-2 + 2)^{2} + (3 - 5)^{2}}$

= $\sqrt{(-2)^{2}}$

= 2

dBC = $\sqrt{(4 - 4)^{2} + (5 - 3)^{2}}$

dBC = $\sqrt{(2)^{2}}$

dBC = 2

Total distance = dAC + dBD + dAD + dBC

Total distance = 6 + 6 + 2 + 2

= 16

I calculate the length of each side and then I sun them up.

4 0

3 years ago

Find the value of x.<br> x = [?]

zzz [600]

Answer:

Step-by-step explanation:

Since both the chords are equidistant from the center of the circle, so their lengths would be same.

x = 2*7 = 14

8 0

3 years ago

A(-3, 0) B(2, 4) C(6, -1) D(1, -5) What is the perimeter and area of quadrilateral ABCD?

Sloan [31]

Answer:

Step-by-step explanation:

7 0

3 years ago

In 36 years, Ishaan will be 3 times as old as he is right now. How old is he right now?

Lady_Fox [76]

Answer: He is 18 years old right now.

Step-by-step explanation:

Let the present age of Ishaan be x

After 36 years,

his age will be x+36

According to question,

it is mentioned that Ishaan will be 3 times as old as he is right now ,

So, we will frame it in equation:

$x+36=3x\\\\36=3x-x\\\\36=2x\\\\x=\frac{36}{2}\\\\x=18\ years$

Hence, he is 18 years old right now.

3 0

3 years ago

Read 2 more answers

I can't figure this equation out, help!!!!!!!!!!!!!!!!!!!!!!!

Vinvika [58]

$\frac{4}{2x-1}-\frac{2}{x}=2;\ D:2x-1\neq0\ \wedge\ x\neq0\Rightarrow x\neq\frac{1}{2}\ \wedge\ x\neq0\\\\\frac{4}{2x-1}=2+\frac{2}{x}\\\\\frac{4}{2x-1}=\frac{2x}{x}+\frac{2}{x}\\\\\frac{4}{2x-1}=\frac{2x+2}{x}\\\\cross\ multiply\\\\(2x-1)(2x+2)=4x\\4x^2+4x-2x-2-4x=0\\4x^2-2x-2=0\\4x^2-4x+2x-2=0$

$4x(x-1)+2(x-1)=0\\(x-1)(4x+2)=0\iff x-1=0\ \vee\ 4x+2=0\\x=1\in D\ \vee\ x=-\frac{1}{2}\in D\\\\Solutions:x=-\frac{1}{2}\ or\ x=1.$

7 0

3 years ago