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-BARSIC- [3]
3 years ago
7

Plz help i need answers ASAP

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
4 0
U need to show us the problem not answers help
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1. write it on a piece of paper
stiv31 [10]

\\ \sf\longmapsto 1\dfrac{1}{2}+2\dfrac{3}{4}

\\ \sf\longmapsto \dfrac{3}{2}+\dfrac{11}{4}

\\ \sf\longmapsto \dfrac{6+11}{4}

\\ \sf\longmapsto \dfrac{17}{4}

2:-

\\ \sf\longmapsto 4\dfrac{3}{7}+6\dfrac{1}{5}

\\ \sf\longmapsto \dfrac{31}{7}+\dfrac{31}{5}

\\ \sf\longmapsto \dfrac{155+225}{35}

\\ \sf\longmapsto \dfrac{380}{35}

\\ \sf\longmapsto 12

3:-

\\ \sf\longmapsto 4\dfrac{2}{5}+5\dfrac{2}{6}

\\ \sf\longmapsto \dfrac{22}{5}+\dfrac{32}{6}

\\ \sf\longmapsto \dfrac{132+160}{30}

\\ \sf\longmapsto \dfrac{292}{30}

4:-

\\ \sf\longmapsto 3\dfrac{7}{7}+3\dfrac{1}{3}

\\ \sf\longmapsto \dfrac{28}{7}+\dfrac{10}{3}

\\ \sf\longmapsto 4+\dfrac{10}{3}

\\ \sf\longmapsto \dfrac{12+10}{3}

\\ \sf\longmapsto \dfrac{22}{3}

7 0
3 years ago
Read 2 more answers
What is 1/2 of 9? EVERYONE THAT ANSWER THIS QUESTION GETS A WALMART GIFT CARD FOR $5. BUT COME ON, YOU CAN DO ALOT WITH $5.. :p
taurus [48]
4.5 or 4 1/2
you can keep the gift card :p
7 0
3 years ago
Read 2 more answers
(-11/20) ÷ (-4/16) =
makvit [3.9K]

Answer:

2.2

Step-by-step explanation:

7 0
3 years ago
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PLZ HELP What is the best approximation of the solution to the system to the nearest integer values? (2, 3) (1, 3) (3, 4) (3, 2)
Kruka [31]

Answer:

  (2, 3)

Step-by-step explanation:

The point with integer coordinates nearest the solution point seems to be (2, 3).

8 0
3 years ago
Read 2 more answers
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 144 millimeters,
valentinak56 [21]

Answer:

The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample  means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean  is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

<em>μ</em> = 144 mm

<em>σ</em> = 7 mm

<em>n</em> = 50.

Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

\bar X\sim N(\mu_{\bar x}=144, \sigma_{\bar x}^{2}=0.98)

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:

P(\bar X-\mu_{\bar x}>2.6)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}} >\frac{2.6}{\sqrt{0.98}})

                           =P(Z>2.63)\\=1-P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

8 0
3 years ago
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