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wariber [46]
3 years ago
7

Chocolates costing $8 per pound are to be mixed with chocolates costing $3 per pound to make a 20 pound mixture. If the mixture

is to sell for $5 per pound, how many pounds of each chocolate should be used? Which of the following equations could be used to solve the problem? 8x + 3x = 5(20) 8x + 3(20) = 5(x + 20) 8x + 3(20 - x) = 5(20)
Mathematics
1 answer:
lubasha [3.4K]3 years ago
6 0

Answer:

  8x + 3(20 - x) = 5(20)

Step-by-step explanation:

If x represents the number of pounds of $8 chocolates, then (20-x) is the number of pounds of $3 chocolates. The cost of the mix attributable to the $8 chocolates will be 8x, and the cost associated with the $3 chocolates will be 3(20-x). The sum of these costs is the cost of the 20 pounds of mix: $5×20.

In equation form, this is ...

  8x + 3(20-x) = 5(20)

_____

The solution is x=8, so 8 lb of $8 chocolates should be mixed with 12 lb of $3 chocolates to make a mix worth $5 per pound.

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Can someone pls help me solve this question!!!!!!!
KiRa [710]

Total of 90 fish:

c + p = 90

Charlie gave 1/4 c to Peter.  Now

Charlie has c - (1/4) c

Peter has p + (1/4) c

Peter gave 2/5 of his to Charlie. Now

Peter has p + (1/4) c - 2/5( p + (1/4) c )

Charlie has c - (1/4) c + 2/5( p + (1/4) c )

And then they had equal number:

c - (1/4) c + 2/5( p + (1/4) c ) = p + (1/4) c - 2/5( p + (1/4) c )

Let's do the easy subtractions then multiply by 20 to clear the fractions,

(3/4) c + 2/5( p + (1/4) c ) = 3/5( p + (1/4) c )

15c + 8p + 2c = 12p + 3c

14c = 4p

7c = 2p

c + p = 90

2c + 2p = 180

2c + 7c = 180

9c = 180

c = 20

p = 70

Answer: Charlie started with 20, Peter with 70

Check:

Initially C:20, P:70

1/4(20)=5 to P

C:15, P:75

(2/5) 75 = 30 to C

C:45, P45

Good


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