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mrs_skeptik [129]
3 years ago
8

A triangle has vertices at points (0, 0), (a, b), and (2a, 0). Select all points that lie on the sides of the triangle. A. (a, 0

) B. (0, b) C. (–a, b) D. (a/2,b/2) E. (a/3,b/4)
Mathematics
1 answer:
RSB [31]3 years ago
4 0

Answer:

A. (a, 0)

D. (a/2,b/2)

Step-by-step explanation:

(a, 0) lies on one side of the triangle, because it is between (0,0) and (2a,0)

(0, b) doesn't lie on one side of the triangle, because only the only point with x-coordinate = 0 is (0,0)

(–a, b) doesn't lie on one side of the triangle, because only positive values are valid

Imagine the triangle with vertices (0,0), (a, 0) and (a,b). Let's call β the angle at vertex (0,0)

tan(β) = b/a

For triangle with vertices (0,0), (a/2, 0) and (a/2,b/2)

tan(β) = (b/2)/(a/2) = b/a

then, (a/2,b/2) lies on one side of the triangle

For triangle with vertices (0,0), (a/3, 0) and (a/3,b/4)

tan(β) = (b/4)/(a/3) = (3/4)*(b/a) ≠ b/a

then, (a/3,b/4) doesn't lie on one side of the triangle

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