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3 years ago

What are the classifications of each system?

2 answers:

5 0

X + 5x = -2 6x = -2 6 6 x = ⁻¹/₃
x + 5y = 4 ⁻¹/₃ + 5y = 4+ ¹/₃ + ¹/₃ 5y = 4¹/₃ 5 5 y = ¹³/₁₅ (x, y) = (⁻¹/₃, ¹³/₁₅)It is inconsistent
y = 3x + 4-2x + y = 4
-2x + y = 4-2x + 3x + 4 = 4 x + 4 = 4 - 4 - 4 x = 0y = 3x + 4y = 3(0) + 4y = 0 + 4y = 4(x, y) = (0, 4)It is consistent and independent.
y = -x + 32x + 2y = 6
2x + 2y = 6 2x + 2(-x + 3) = 62x + 2(-x) + 2(3) = 6 2x - 2x + 6 = 6 6 = 6It is consisteent
5x + 2y = -4 5x - 2y = 3 10x = -1 10 10 x = ⁻¹/₁₀
5x + 2y = -45(⁻¹/₁₀) + 2y = -4 ⁻¹/₂ + 2y = -4 + ¹/₂ + ¹/₂ 2y = -3¹/₂ 2 2 y = -1³/₄ (x, y) = (⁻¹/₁₀, -1³/₄)It is consistent and independent.

sorry if i used your thing but i took the quiz and this is right im sorry but that's wrong :(

xz_007 [3.2K]3 years ago

4 0

X + 5x = -2
6x = -2
6 6
x = ⁻¹/₃

  x + 5y = 4
⁻¹/₃ + 5y = 4
+ ¹/₃ + ¹/₃
5y = 4¹/₃
5 5
  y = ¹³/₁₅
  (x, y) = (⁻¹/₃, ¹³/₁₅)
It is consistent and independent.

y = 3x + 4
-2x + y = 4

  -2x + y = 4
-2x + 3x + 4 = 4
x + 4 = 4
- 4 - 4
x = 0
y = 3x + 4
y = 3(0) + 4
y = 0 + 4
y = 4
(x, y) = (0, 4)
It is consistent and independent.

y = -x + 3
2x + 2y = 6

2x + 2y = 6
  2x + 2(-x + 3) = 6
2x + 2(-x) + 2(3) = 6
2x - 2x + 6 = 6
  6 = 6
It is consistent and dependent.

5x + 2y = -4
5x - 2y = 3
10x = -1
10 10
x = ⁻¹/₁₀

5x + 2y = -4
5(⁻¹/₁₀) + 2y = -4
⁻¹/₂ + 2y = -4
+ ¹/₂   + ¹/₂
2y = -3¹/₂
2 2
y = -1³/₄
  (x, y) = (⁻¹/₁₀, -1³/₄)
It is consistent and independent.

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nadya68 [22]

Answer:

50=(3x)x

Step-by-step explanation:

50=(3x)x. The question is only asking for the inequality of the problem. Since the area of a rectangle is L x W, you would write L as 3x and W as x, and since the area of the rectangle is given, you can set the area as 50.

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1 year ago

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What is the simplified sum of 3x/x-4 + x-3/2x

zubka84 [21]

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▹ Answer

-1 - 1/2x

▹ Step-by-Step Explanation

3x ÷ x - 4 + x - 3 ÷ 2x

Divide and Rewrite:

3 * 1 - 4 + x - 3 ÷ 2 * x

Calculate:

3 - 4 + x - 3/2x

-1 + x - 3/2x

= -1 - 1/2x

Hope this helps!

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4 0

3 years ago

Read 2 more answers

1. Jill had the following scores on quizzes. 1 quiz: 1 3 quizzes: 2 4 quizzes: 3

Irina-Kira [14]

The mean score is 3.08.

There is 1 quiz with score 1, so 1 point; 3 quizzes with score 2 for 3*2 = 6 points; 4 quizzes with score 3 for 4*3 = 12 points; 4 quizzes with score 4 for 4*4 = 16 points; and 1 quiz with score 5 for 5 points.

This is a total of 1+6+12+16+5 = 40 points.

This is out of 1+3+4+4+1 = 13 quizzes.

40/13 = 3.08

7 0

3 years ago

Find the area of the composite figure.

Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

According to the Figure Given:

Total Horizontal Distance = 14 in

Length = 6 in

To Find :

The Area of the composite figure

Solution:

Firstly we need to find the area of Rectangular part.

So We know that,

$\boxed{ \rm \: Area \: of \: Rectangle = Length×Breadth}$

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

$\boxed{\rm \: Breadth = total \: distance - Radius}$

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

$\longrightarrow\rm \: Length \: of \: the \: circle = Radius$

Since Length = 6 in ;

$\longrightarrow \rm \: 6 \: in = radius$

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

Total Horizontal Distance= 14
Radius = 6

$\longrightarrow\rm \: Breadth = 14-6$

$\longrightarrow\rm \: Breadth = 8 \: in$

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

Length = 6
Breadth = 8

$\longrightarrow\rm \: Area \: of \: Rectangle = 6 \times 8$

$\longrightarrow \rm \: Area \: of \: Rectangle = 48 \: in {}^{2}$

Then, We need to find the area of Quarter circle :

We know that,

$\boxed{\rm Area_{(Quarter \; Circle) } = \cfrac{\pi{r} {}^{2} }{4}}$

Now Substitute their values:

r = radius = 6
π = 3.14

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 6 {}^{2} }{4}$

Solve it.

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 36}{4}$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}$

$\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \: {in}^{2}$

Now we can Find out the total Area of composite figure:

We know that,

$\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}$

So Substitute their values:

$\rm Area_{(rectangle)}$ = 48
$\rm Area_{(Quarter Circle)}$ = 28.26

$\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26$

Solve it.

$\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}$

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

$\rule{225pt}{2pt}$

I hope this helps!

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2 years ago

A model of the is 2.9 ft tall and 1.2 ft wide. The Eiffel Tower is actually 410 ft wide. What is the actual height of the Eiffel

AVprozaik [17]

By setting up proportions and cross multiplying, the height would be 990.8.

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3 years ago