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ziro4ka [17]
4 years ago
6

Help me with this question

Mathematics
1 answer:
ziro4ka [17]4 years ago
6 0
Using the slope-intercept form of y = mx + b, just plug in for the values given by the graph.

Your Y-intercept (0, y), you plug in the y value as B. M is where you put your slope. 

So for the second one (top right), you have a Y-int of -2 or (0, -2) and a slope/m of 1/1 = 1. So your equation would be y = 1x - 2 or y = x - 2. 


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3 years ago
One number is 8 more than another. If the sum of the two numbers is 166​, find the two numbers.
Igoryamba

\bf \underline{Given : }

  • One number is 8 more than another.

  • Sum of the two numbers is 166.

\bf \underline{To \: find \: out : }

Find the two numbers.

\bf \underline{Solution : }

Let the one number be x.

Then,another number = x + 8

<u>According to the question </u><u>,</u>

Sum of the two numbers is 166. [ Given ]

\sf\implies \: x + x + 8 = 166

\sf \implies \: 2x + 8 = 166

\sf \implies \: 2x = 166 - 8

\sf\implies \: 2x = 158

\sf \implies \: x =  \cancel \dfrac{158}{2}

\sf \implies \: x = 79

One number = x = 79

Another number = x + 8 = 79 + 8 = 87

4 0
3 years ago
The sum of 13 and twice n
Llana [10]

Answer:

13 + 2n

Step-by-step explanation:

7 0
3 years ago
3 + 4ab+ 4ab - 5b + m
Rainbow [258]

Answers:  

  • Number of terms: 5
  • Coefficients:  4, 4, -5 and 1
  • Constant term:  3

===================================================

Explanation:

Each term is separated by a plus sign or a minus sign. We could rewrite the 4ab-5b portion as 4ab + (-5b) to help get everything separated by a plus sign.

The five terms are

  • 3
  • 4ab
  • 4ab
  • -5b
  • m

The coefficients are the numbers just to the left of the variable. For a term like 4ab, the coefficient is 4. For the term "m", we can think of it as 1m so we can see it has a coefficient of 1.

The constant term is the term that doesn't have any variable attached to it. That would be the "3" as the first term.

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2 years ago
Select the correct answer from the drop-down menu find the surface area of this triangular prism
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Would you please provide us with the options so we can help thanks
7 0
3 years ago
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