Answer:
Explanation:
Data given and notation
represent the sample mean
represent the standard deviation for the sample
sample size
represent the value that we want to test
represent the significance level for the hypothesis test.
t would represent the statistic (variable of interest)
represent the p value for the test (variable of interest)
State the null and alternative hypotheses.
We need to conduct a hypothesis in order to determine if the mean is lower than 5600, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:
(1)
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
Calculate the statistic
We can replace in formula (1) the info given like this:
Answer:
The answer is 5.73%
Explanation:
Given Coupon rate=5.5%; Years of maturity= 12years, Face value bonds= $1,000, Price=98.2
NPER= Years of maturity *2= 12*2=24
PMT= (Face value * coupon rate)/2= (1000*5.5)/2= 5500/2= 2.75
Therefore:
Rate = (NPER, PMT, -Price, Face value)= (24, 2.75, -98.2, 1000)= 2.87%
Yield to maturity= Rate *2= 2.87*2= 5.73%
Answer:
$19.20
Explanation:
Computation for the unit product cost that would appear on the job cost sheet for this job.
First step is to compute the Total Product cost
Job 243
Direct material $ 51,870
Direct labor (435*11) 4,785
Overhead (516*13) 6,708
Total Product cost $63,363
Now let Compute the unit product cost
Unit product cost=$63,363/3,300 units
Unit product cost =$19.20
Therefore the unit product cost that would appear on the job cost sheet for this job is $19.20
<span>The Gini ratio for lifetime income is less than the Gini ratio for annual income.</span>
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