Answer:
The method of solving "by substitution" works by solving one of the equations (you choose which one) for one of the variables (you choose which one), and then plugging this back into the other equation, "substituting" for the chosen variable and solving for the other.
Step-by-step explanation:
I think 6 and -8, I am not too positive
Standard reduction of order procedure: suppose there is a second solution of the form

, which has derivatives



Substitute these terms into the ODE:



and replacing

, we have an ODE linear in

:

Divide both sides by

, giving

and noting that the left hand side is a derivative of a product, namely
![\dfrac{\mathrm d}{\mathrm dx}[wx]=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Bwx%5D%3D0)
we can then integrate both sides to obtain


Solve for

:


Now

where the second term is already accounted for by

, which means

, and the above is the general solution for the ODE.
Answer:
Brett's statement is true
Step-by-step explanation:
A negative times a negative will always equal a positive number.
If you see two negative numbers being multiplied together, you can ignore the negative signs and treat them both like positive numbers.
-4 x -5 = 20
4 x 5 = 20
The Answer Is B)...................