Width =3.5, length = 4

Let's make a few equations to summarize what we know.:
a = 14
l = 2w -3
a = wl

Now let's substitute the expression for l into the expression for area and solve.
a = w(2w - 3)
a = 2w^2 - 3w
14 = 2w^2 - 3w

0 = 2w^2 - 3w - 14

which factors into
(2w - 7) (w + 2)

Solving for w
2w - 7 = 0
2w = 7
w = 3.5

w+2 = 0
w = -2

So w can be either 3.5 or -2. Since a negative width doesn't make sense, w = 3.5

Let's verify
w = 3.5
l = 2w - 3
l = 2*3.5 - 3
l = 7 - 3
l = 4
a = wl
a = 3.5 * 4
a = 14

So the width is 3.5 and the length is 4.

3 0

3 years ago

16. Suppose Eva has 12 3/4 pounds of flour. The day's baking will require triple that amount.

egoroff_w [7]

Answer:

Option D

Step-by-step explanation:

Given the following question:

$12 \frac{3}{4} \times3$

In order to find the answer, we have to convert the mixed number and then multiply by three, since how Eva needs triple the amount for today's baking.

$12 \frac{3}{4} \times3$
$12\frac{3}{4} =4\times12=48+3=51=\frac{51}{4}$
$3=\frac{3}{1}$
$\frac{51}{4} \times\frac{3}{1}$
$51\times3=153$
$4\times1=4$
$=\frac{153}{4}$

<u>Convert the improper fraction back into a mixed number:</u>

$\frac{153}{4}$
$\frac{153}{4} =153\div4=38\frac{1}{4}$
$=38\frac{1}{4}$

Which means Eva needs "38 1/4 pounds of flour" or option D for today's baking.