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3 years ago

14

3/6 what is the sum in unit fractions

1 answer:

julia-pushkina [17]3 years ago

6 0

Exact form:
1 / 2

Decimal foem :
0.5

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Which experimental design compares two groups (randomly formed) on the same task, such as movement speed

anygoal [31]

Between-group design compares two groups (randomly formed) on the same task, such as movement speed.

Given things that there are two groups that are randomly formed for the same task.

A between-group design in experimental design is an experiment in which two or more groups of individuals are assessed simultaneously by separate testing factors. This design is typically used instead of, or in conjunction with, the within-subject design, which applies identical modifications of circumstances to each participant in order to monitor the reactions.

Learn more about experimental designs at brainly.com/question/17280313

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1 year ago

Factor the GCF:<br> 24x3 + 8x

disa [49]

Answer:

8x(3x^2 +1)

Step-by-step explanation:

24x^3 + 8x

We can factor out 8x

8x(3x^2 +1)

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3 years ago

Use the rule (x,y) (3x,2y) to find the image for the preimage defined by the given points.

Elina [12.6K]

Answer: The points of the images are (9,10), (15,6), (6,4) and the image is not a rigid motion because the shape changes in side.

Step-by-step explanation:

Since it gives you the scale factor then find they coordinates by multiplying the coordinates by the scare factor.

A(3,5) → (3*3,5*2) → (9,10)

B( 5,3) → (5*3, 3*2) → (15,6)

C ( 2,3)→ (2*3, 2*2)→ ( 6,4)

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3 years ago

Sandra waits tables at Polly's Tamales. While she is working, she receives a discount on any food she buys. If an item normally

Musya8 [376]

Answer: 6

Step-by-step explanation: 2/3 of 9 = 6

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2 years ago

The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st

Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

$v=\frac{d}{t}$ .

Applying this to our problem we have that

$v=\frac{200m}{6.509s}= 30.726m/s$ .

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that $v=\frac{d}{t}$ . This formula implies that

$t=\frac{d}{v}$ .

First, observer that $19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s$ .

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, $v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.$

Then, applying 1) we have that

$t=\frac{200m}{36.003m/s}=5.5549s.$

So, Sam Whittingham’s time through the 200 m was 5.5549s.

5 0

3 years ago