Answer:
Yes, the function satisfies the hypothesis of the Mean Value Theorem on the interval [1,5]
Step-by-step explanation:
We are given that a function
![f(x)=ln(x)](https://tex.z-dn.net/?f=f%28x%29%3Dln%28x%29)
Interval [1,5]
The given function is defined on this interval.
Hypothesis of Mean Value Theorem:
(1) Function is continuous on interval [a,b]
(2)Function is defined on interval (a,b)
From the graph we can see that
The function is continuous on [1,5] and differentiable at(1,5).
Hence, the function satisfies the hypothesis of the Mean Value Theorem.
"Rowanda 7.24 km and Terrance 5.1 km" is correct:
Rowanda jogged farther than Terrance so the third version, where 3.51km is smaller than 5.65km, can be ruled out. Then you have to look for the difference between the two values of the others--it has to be a difference of 2.14km. in this case it works:
7.24km - 5.1km = 2.14km
this shows she jogged 2.14km more than Terrance :)
The same thing works for the first version with 6.5km-4.36km=2.14km :) so the first one is correct, too
Answer:
X=-12
Step-by-step explanation:
Subtract -5/2 on both sides:
X/3+5/2-5/2=-3/2-5/2
X/3=-8/2
X/3=-4
Multiply both sides by 3:
X/3*3=-4*3
X=-12
Answer: the height would be 15
Step-by-step explanation:
v= pi*radius^2*height
1215pi mm= pi*9^2*height
1215pi mm= pi*81*height
(divide by pi on both sides, which isolates pi on both sides)
1215 mm= 81*height
(divide by 81 on both sides, which would isolate 81 on the right side of the equation)
1215/81= 15= height