X^2 + y^2 - 2x + 2y - 1 = 0
(x^2 - 2x) + (y^2 + 2y) - 1 = 0
(x^2 - 2x + 1) + (y^2 + 2y + 1) - 1 - 1 - 1 = 0
(x - 1)^2 + (y + 1)^2 - 3 = 0
(x - 1)^2 + (y + 1)^2 = 3
Answer:
SD = 2x
UD = x
Step-by-step explanation:
The hypotenuse of a 30-60-90 triangle is 2 times the length of the shorter leg.
SU is the shorter leg = x
So, SD = 2x
The longer leg of a 30-60-90 triangle is
times the shorter leg.
So, UD = x
Answer:
<h2>Q9. C.</h2><h2>Q10. B.</h2>
Step-by-step explanation:


you start by adding any 2 numbers and then multiplying the sum by 3